实现iota函数[亲测有效]

void Reverse(char *s)
{
	char temp;
	char *p = s; 
	char *q = s;

	while (*p != '\0')
	{
		p ++;
	}
	q --;
	while (p > q)
	{
		temp = *p;
		*q ++ = *p;
		*q -- = temp;
	}

	return s;
}

char* My_Itoa(int nval)
{
	static char cBuff[100] = {0};
	int i = 0;
	int nTempVal = nval;

	if (nval < 0)
	{
		nval = -1 * nval;
	}

	do
	{
		cBuff[i ++] = (nval % 10)  + '0';
		nval = nval / 10;

	}while (nval > 0);

	if (nTempVal < 0)
	{
		cBuff[i ++] = '-';
	}
	cBuff[i] = '\0';

	return cBuff;
}