Oracle 10.2.0.4 sql关联查询语句中含有 connect by 导致报错出现ORA-00600

星哥玩云

发布于 2022-08-18 14:16:18

4550

发布于 2022-08-18 14:16:18

写了个视图导致出现报错：网上说是Oracle 10.2.0.4和10.2.0.3版本的一个bug

SELECT A.*FROM PL_PLAN_BASE A left JOIN (SELECT B.CATEGORY_ID, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH( B.CLASS_NAME,'/'),'[^/]+',1,1,'i') FIRST_NAME, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH( B.CLASS_NAME,'/'),'[^/]+',1,2,'i') SECOND_NAME, B.CLASS_NAME THIRD_NAME FROM PC_CATEGORY_BASE B START WITH B.PARENT_ID IS NULL CONNECT BY B.PARENT_ID=PRIOR B.CATEGORY_ID ) C ON A.CATEGORY_ID=C.CATEGORY_ID LEFT JOIN (SELECT DEPT_NAME,DEPT_CODE FROM BI_DEPT ) D ON D.DEPT_CODE=A.APPLY_DEPT_CODE LEFT JOIN (SELECT T.CATEGORY_ID,D.DEPT_NAME,T.ORG_CODE FROM PC_CATEGORY_ORG T,BI_DEPT D WHERE T.CENTRALIZED_DEP_CODE=D.DEPT_CODE )E ON (E.CATEGORY_ID =a.Category_Id AND E.ORG_CODE=A.CRT_ORG_CODE) where a.data_state='0' and a.plan_org_name not like '%测试%' and a.plan_material_name not like '%测试%' and a.crt_org_name not like '%null%'；

1 如果关联语句不是很多是不会报错：比如下面这样是可以查出来

SELECT A.*FROM PL_PLAN_BASE A left JOIN (SELECT B.CATEGORY_ID, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH( B.CLASS_NAME,'/'),'[^/]+',1,1,'i') FIRST_NAME, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH( B.CLASS_NAME,'/'),'[^/]+',1,2,'i') SECOND_NAME, B.CLASS_NAME THIRD_NAME FROM PC_CATEGORY_BASE B START WITH B.PARENT_ID IS NULL CONNECT BY B.PARENT_ID=PRIOR B.CATEGORY_ID ) C ON A.CATEGORY_ID=C.CATEGORY_ID LEFT JOIN (SELECT DEPT_NAME,DEPT_CODE FROM BI_DEPT ) D ON D.DEPT_CODE=A.APPLY_DEPT_CODE

2 如果关联语句太多就会报错比如上面的.

3 解决办法：

1 修改SQL语句，不要这个递归，去掉这个connect by ；

2 这么修改，修改这个参数调整优化器的版本： alter session set optimizer_features_enable='10.2.0.1';

3 修改这个参数：_optimizer_connect_by_cost_based 为 false；

我们这边是针对本session的进行语句级修改，只针对这个语句，所以不影响整个库：

ALTER SESSION SET " _optimizer_connect_by_cost_based "=false;

我这边选择第三种，但是我们这个是要经常查询的，我可以直接加到 hint 里面去，就可以：

CREATE OR REPLACE VIEW V_TW_PURCHASE_PL_STAT1 AS

SELECT /*+ OPT_PARAM('_optimizer_connect_by_cost_based' 'false') */ A.PLAN_ID, DECODE(A.PLAN_TYPE,'0','年初计划','1','中期调整',A.PLAN_TYPE) PLAN_TYPE, A.PLAN_YEAR, A.CATEGORY_ID, C.FIRST_NAME, ................................. FROM PL_PLAN_BASE A left JOIN (SELECT B.CATEGORY_ID, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH( B.CLASS_NAME,'/'),'[^/]+',1,1,'i') FIRST_NAME, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH( B.CLASS_NAME,'/'),'[^/]+',1,2,'i') SECOND_NAME, B.CLASS_NAME THIRD_NAME FROM PC_CATEGORY_BASE B START WITH B.PARENT_ID IS NULL CONNECT BY B.PARENT_ID=PRIOR B.CATEGORY_ID ) C ON A.CATEGORY_ID=C.CATEGORY_ID LEFT JOIN (SELECT DEPT_NAME,DEPT_CODE FROM BI_DEPT ) D ON D.DEPT_CODE=A.APPLY_DEPT_CODE LEFT JOIN (SELECT T.CATEGORY_ID,D.DEPT_NAME,T.ORG_CODE FROM PC_CATEGORY_ORG T,BI_DEPT D WHERE T.CENTRALIZED_DEP_CODE=D.DEPT_CODE )E ON (E.CATEGORY_ID =a.Category_Id AND E.ORG_CODE=A.CRT_ORG_CODE) where a.data_state='0' and a.plan_org_name not like '%测试%' and a.plan_material_name not like '%测试%' and a.crt_org_name not like '%null%';

再次查询就不会报错：可以查出来。