力扣做题笔记（1）：重新排列数组

输入：nums = [2,5,1,3,4,7], n = 3
输出：[2,3,5,4,1,7] 
解释：由于 x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 ，所以答案为 [2,3,5,4,1,7]

class Solution {
    public int[] shuffle(int[] nums, int n) {
        int[] Array = new int[2 * n];
        int[] Arrayx = new int[n];
        int[] Arrayy = new int[n];
        int a = 0, b = 0;
        for (int i = 0; i < Arrayx.length; i++) {//把数组的前n个给x数组
            Arrayx[i] = nums[i];
        }
        for (int i = 0; i < Arrayy.length; i++) {//把数组的后n个给y数组
            Arrayy[i] = nums[i+n];
        }
        for (int i = 0; i < Array.length; i++) {//把x和y数组交叉合并
            if (i % 2 ==0){
                Array[i] = Arrayx[a++];
            } else {
                Array[i] = Arrayy[b++];
            }

        }
        return Array;
    }

}