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include irvine32.inc; .data i dword 0; sum qword 0; str1 byte “请输入16进制的(32位整数)乘数和被乘数”,0 str2 byte “乘积为:”,0; j dword 0;
.code
main proc
L1: mov edx,offset str1; call writestring;
mov j,0; mov eax,0;eax为(低32位)乘积值; mov ebx,0;edx为(低32位)乘积值的中间值 mov edx,0; mov esi,0;dsi为(高32位)乘积值的中间值 mov edi,0;edi为(高32位)乘积值; mov cl,0;cl为移位的位数
call readhex; cmp eax,80000000h;
jna L4; neg eax; inc j; L4: mov ebx,eax; ebx存储乘数(来移位的) ;call writeint;
call readhex; cmp eax,80000000h;
jna L5; neg eax; inc j; L5: mov i,eax; ;call writeint; mov eax,0; cmp ebx, 0; jne L2; cmp i,0; je finally;
L2: cmp ebx,0; jz quit; shr ebx,1; jnc next;if(ZF==0)
mov esi,0;每次都要清零; mov edx,i;
shld esi,edx,cl; shl edx,cl;
add eax,edx; jnc L3;if(ZF==0) add edi,1;
L3: add edi,esi; next: inc cl; jmp L2;
quit: call crlf; mov edx,offset str2; call writestring; mov ebx,eax;
cmp j,1; jne L6; add edi,80000000h ;call writestring L6:
mov eax,edi; call writehex;
mov eax,ebx; call writehex;
call crlf;
jmp L1;
finally:
exit main endp; end main
转载于:https://www.cnblogs.com/hqu-ye/archive/2013/02/25/2932588.html
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