Random的nextInt用法

	Random random = new Random();    	System.out.println(random.nextInt() % 100);

但是在运行的时候，发现上面的方法有时会产生负数，通过查看Random类的源代码才发现，不带参数的nextInt会产生所有有效的整数，所以当然会有负数产生了。
正确的解法应该是：
	Random random1 = new Random();	System.out.println(random1.nextInt(100)); //100是不包含在内的，只产生0~99之间的数。应用：
生成乱序不重复数组
package com.cn.wuliu.utils;import java.util.Random;public class Arith {      //对给定数目的自0开始步长为1的数字序列进行不重复乱序      public static int[] getSequence(int maxnum) {          int[] sequence = new int[maxnum];          for(int i = 0; i < maxnum; i++){              sequence[i] = i;          }//         System.out.println(Arrays.toString(sequence));//		[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]          Random random = new Random();          for(int i = 0; i < maxnum; i++){              int p = random.nextInt(maxnum);              int tmp = sequence[i];              sequence[i] = sequence[p];              sequence[p] = tmp;          }          random = null;          return sequence;      } 	//对给定数目的自minnum开始步长为1到maxnum的数字序列进行不重复乱序	public static int[] getSequence(int minnum,int maxnum) {    	  int num = maxnum - minnum + 1;          int[] sequence = new int[num];          for(int i = 0; i < num; i++){              sequence[i] = i + minnum;          }//          System.out.println(Arrays.toString(sequence));          Random random = new Random();          for(int i = 0; i < num; i++){              int p = random.nextInt(num);              int tmp = sequence[i];              sequence[i] = sequence[p];              sequence[p] = tmp;          }          random = null;          return sequence;      }       public static void main(String[] agrs){    	  Arith arith = new Arith();    	  int[] i = arith.getSequence(10);    	  for(int n=0;n<i.length;n++){    		  System.out.print(i[n]);    	  }    	  System.out.println();    	  int[] j = arith.getSequence(3,8);    	  for(int n=0;n<j.length;n++){    		  System.out.print(j[n]);    	  }      }}