大家好,又见面了,我是你们的朋友全栈君。
输入
2
3 1
4 3
输出
Impossible
2 1 4 3
3 4 1 2
4 3 2 1
题解 找规律+构造
#include<bits/stdc++.h>
using namespace std;
const int N = 1001;
int ch[N][N];
int lowbit(int x){
return x & (-x);
}
int main(){
int n,k;
int T;
cin>>T;
while(T --){
cin>>n>>k;
if(k >= lowbit(n))cout<<"Impossible"<<endl;
else{
for(int i = 1;i <= n;i ++){
ch[0][i] = i;
}
for(int t = 1;t <= k;){
for(int k = t;k < 2 * t;k ++){
int offset = t;
for(int z = 1;z <= n;z += 2 * offset){
for(int j = z;j < z + offset;j ++){
ch[k][j] = ch[k - offset][j + offset];
}
for(int j = z + offset;j < z + 2 * offset;j ++){
ch[k][j] = ch[k - offset][j - offset];
}
}
}
t *= 2;
}
for(int i = 1;i <= k;i ++){
cout<<ch[i][1];
for(int j = 2;j <= n;j ++){
cout<<" " << ch[i][j];
}
cout<<endl;
}
}
}
return 0;
}
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