题目
判断第一个字符串是否包含第二个字符串
function compare(str1, str2) {
if (str1 === str2) {
return true
}
let arr1 = [...str1]
let arr2 = [...str2]
if (arr2.length > arr1.length) {
return false
}
for (let i = 0; i < arr1.length; i++) {
if (i > (arr1.length - arr2.length - 1)) {
break
}
if (arr1[i] === arr2[0]) {
let m = i
let flag = true
for (let k = 0; k < arr2.length; k++) {
if (arr2[k] === arr1[m]) {
m++
} else {
flag = false
}
}
if (flag) {
return true
}
}
}
return false
}
let str1 = 'aabbc'
let str2 = 'aabb'
console.log(compare(str1, str2))发布者:全栈程序员栈长,转载请注明出处:https://javaforall.cn/171712.html原文链接:https://javaforall.cn