1784. 检查二进制字符串字段-今日份快乐

class Solution {
    public boolean checkOnesSegment(String s) {
        int len = s.length();
        char[] chs = s.toCharArray();
        int index = -1;
        int seg1 = 0;
        for(int i=0;i<len;i++){
            if(chs[i]=='1'){
                if(seg1==1) return false;
                // if(index+1!=i) return false; 
            }else{
                if(i-1>=0&&chs[i-1]=='1') seg1++;
                index = i;
            }
        }
        return true;
    }  
}