C++编程之美-数字之魅(代码清单2-23)

for(i = 0, j = n - 1; i < j; )
     if(arr[i] + arr[j] == Sum)
          return (i, j);
     else if(arr[i] + arr[j] < Sum)
          i++;
     else
          j--; 
return（-1, -1）;