Python字符串遍历_Python自学第九节

>>> a = 'ILovePython'
>>> for i in a:
...     print(i,end='')
... 
ILovePython>>> 

>>> a,b,c ='123'
>>> a
'1'
>>> b
'2'
>>> c
'3'

>>> for i in range(100,1000):
...     bai = str(i)[0]   #取i的第一位数即为百位数
...     shi = str(i)[1]   #取i的第二位数即为十位数
...     ge = str(i)[2]   #取i的第三位数即为个位数
------以上需要数值转换为字符------
...     if i == int(bai)**3 + int(shi)**3 + int(ge)**3:   #此步需要转换回数值
...             print(i)
... 
153
370
371
407

------优化步骤------
>>> for i in range(100,1000):
...     bai,shi,ge = map(int,str(i))   #一步把str(i)转换为数值
...     if i == bai**3 + shi**3 + ge**3:
...             print(i)
... 
153
370
371
407

>>> a = '}~144_0t_em0c14w{galf'
>>> a [::-1]
'flag{w41c0me_t0_441~}'
直接反转得到flag{  }