利用Python解读物理电学基础应用

def N_times(Ts): Npd = input('并联支路电流:zl ｜ 并联总电流:gl | 总电压：cu') if Npd.lower() == 'zl': I_one = "干路电流为___" I_two = '支路电流为___' N1 = float(input('输入{}{}：'.format(I_one,Ts))) N2 = float(input('输入{}{}：'.format(I_two,Ts))) elif Npd.lower() == 'gl': I_one_1 = '支路1电流为___' I_one_2 = '支路2电流为___' N1 = float(input('输入{}{}：'.format(I_one_1,Ts))) N2 = float(input('输入{}{}：'.format(I_one_2,Ts))) elif Npd.lower() == 'cu': R_one_1 = 'R1两端电压为___' R_one_2 = 'R2两端电压为___' N1 = float(input('输入{}{}：'.format(R_one_1,Ts))) N2 = float(input('输入{}{}：'.format(R_one_2,Ts))) return N1, N2,Npddef R_total_chuanl(one,two): R = one + two print('欢迎来到求串联电阻的步骤：R总= R1+R2 = {}Ω +{}Ω ={}Ω '.format(A, B, R))def I_total_bingl(one,two,Npd): if Npd == 'gl': I = one + two print('求得干路并联电流为：I总= I1+I2 = {}A +{}A ={}A '.format(one, two, I)) elif Npd == 'zl': if two < one: one,two = two,one I2 = two - one print('支路L2电流为:I2=I-I1={}A-{}A={:.1f}A'.format(two,one,I2))def U_total_chl(one,two,Npd): if Npd == 'cu': U = one + two print('串联电路总电压为：U总= U1+U2 = {}V +{}V ={}V '.format(one, two, U)) print(f'串联电路电压规律为u=u1+u2，U总={U}V')Pd = input(''' 请输入 1-并联电流 2-串联电阻 3-串联电压\n''')if Pd == '1': Ts = 'A' A,B,Npd = N_times(Ts) I_total_bingl(A,B,Npd)elif Pd == '2': Ts = 'Ω ' A,B = N_times(Ts) R_total_chuanl(A,B)elif Pd == '3': Ts = 'V' A,B,Npd = N_times(Ts) U_total_chl(A,B,Npd)