去除字符串中的空白符

#include <stdio.h>
int StringStripWS(char* pStr, int type)
{
char* pStrback = pStr;
switch (type)
{
case 1: // 去除左侧空白字符
if (*pStrback == ‘ ‘  *pStrback == ‘\t’)
{
while (*pStrback == ‘ ‘  *pStrback == ‘\t’) pStrback++;
while (*pStr++ = *pStrback++);
}
break;
case 2: // 去除右侧空白字符
while (*pStr) pStr++;
pStr–;
while (*pStr == ‘ ‘  *pStr == ‘\t’)
{
*pStr = ‘\0’;
pStr–;
}
break;
case 3: // 去除所有空白字符
while (*pStr)
{
if (*pStr == ‘ ‘  *pStr == ‘\t’)
{
pStr++;
continue;
}
else
{
*pStrback++ = *pStr++;
}
}
*pStrback = ‘\0’;
break;
}
return 0;
}
int main(int argc, char* argv[])
{
char buf[] = “      my     name     is     dengjia      “;
printf(“原始字符串内容为 : –%s–\n”, buf);
StringStripWS(buf, 1);
printf(“去除左侧空白符后 : –%s–\n”, buf);
StringStripWS(buf, 2);
printf(“去除右侧空白符后 : –%s–\n”, buf);
StringStripWS(buf, 3);
printf(“去除全部空白符后 : –%s–\n”, buf);
return 0;
}