golang面试题：对未初始化的的chan进行读写，会怎么样？为什么？

package main
// 写未初始化的chan
func main() {
	var c chan int
	c <- 1
}

// 输出结果
fatal error: all goroutines are asleep - deadlock!

goroutine 1 [chan send (nil chan)]:
main.main()
        /Users/admin18/go/src/code.byted.org/linzhaolun/repos/main.go:6 +0x36

package main
import "fmt"
// 读未初始化的chan
func main() {
	var c chan int
	num, ok := <-c
	fmt.Printf("读chan的协程结束, num=%v, ok=%v\n", num, ok)
}

// 输出结果
fatal error: all goroutines are asleep - deadlock!

goroutine 1 [chan receive (nil chan)]:
main.main()
        /Users/admin18/go/src/code.byted.org/linzhaolun/repos/main.go:6 +0x46

//在 src/runtime/chan.go中
func chansend(c *hchan, ep unsafe.Pointer, block bool, callerpc uintptr) bool {
	if c == nil {
      // 不能阻塞，直接返回 false，表示未发送成功
      if !block {
        return false
      }
      gopark(nil, nil, waitReasonChanSendNilChan, traceEvGoStop, 2)
      throw("unreachable")
	}
  // 省略其他逻辑
}

//在 src/runtime/chan.go中
func chanrecv(c *hchan, ep unsafe.Pointer, block bool) (selected, received bool) {
    //省略逻辑...
    if c == nil {
        if !block {
          return
        }
        gopark(nil, nil, waitReasonChanReceiveNilChan, traceEvGoStop, 2)
        throw("unreachable")
    }
    //省略逻辑...
}