用C语言实现闰年查询器的方法

#include<stdio.h>
int main()
{
	int year = 0;
	scanf("%d", &year);
	if ((year % 4 == 0) && (year % 100 != 0) || (year % 400 == 0))
	{
		printf("%d年是闰年。\n",year);
	}
	else
	{
		printf("%d年不是闰年",year);
	}
	return 0;
}

#include<stdio.h>
int leap_year(int x, int y)
{
	int b = 0;
	for (x; x <= y; y++)
	{
		if ((x % 4 == 0) && (x % 100 != 0) || (x % 400 == 0))
		{
			return x;
		}
		else
		{
			return 0;
		}
	}
}
int main()
{
	int year1, year2;
	int count = 0;
	printf("请输入要查询的范围\n");
	scanf("%d%d", &year1, &year2);
	int n = year2 - year1;
	//int a=0;
	if (n < 0)
	{
		printf("输入错误请重新输入\n");
	}
	else if (n < 4)
	{
		if(leap_year(year1,year2)!=0)
		{
			printf("%d年到%d年的闰年有%d年，只有1年是闰年。\n", year1, year2, year1);
		}
		else
		{
			printf("%d年到%d年没有闰年\n", year1, year2);
		}
	}
	else
	{
		printf("%d到%d的闰年有:", year1, year2);
		for (year1; year1 < year2; year1++)
		{
			if (leap_year(year1, year2) != 0)
			{
				printf("%d年 ", year1);
		}
	}
	return 0;
}