如何在批处理中给文件动态命名

import pandas as pd

# 创建一个日期范围
timelist = pd.date_range(start="2023-01-01", end="2023-01-10").tolist()

# 打印结果
for date in timelist:
    print(date.strftime("%Y-%m-%d"))

2023-01-01
2023-01-02
2023-01-03
2023-01-04
2023-01-05
2023-01-06
2023-01-07
2023-01-08
2023-01-09
2023-01-10

for i in timelist:
    filename = f"{i}.txt"  # 假设您想创建或打开一个扩展名为.txt的文件
    with open(filename, 'w') as file:  
        # 在这里写入您想放入文件的内容
        file.write("abc")

for i in timelist:
    filename = "{}.txt".format(i)  # 构造文件名
    with open(filename, 'w') as file:
        # 写入内容
        file.write("Some content")

for i in timelist:
    filename = "%s.txt" % i  # 构造文件名
    with open(filename, 'w') as file:
        # 写入内容
        file.write("Some content")