const gulp = require('gulp');
const $ = require('gulp-load-plugins')();
const source = require('vinyl-source-stream');
const browserify = require('browserify');
gulp.task('build', () =>
browserify('./src/app.js').bundle()
.pipe(source('app.js'))
.pipe(gulp.dest('./build')) // OK. app.js is saved.
.pipe($.rename('app.min.js'))
.pipe($.streamify($.uglify())
.pipe(gulp.dest('./build')) // Fail. app.min.js is not saved.
);
当file.contents是流时,当前不支持到多个目标的管道。此问题的解决方法是什么?
https://stackoverflow.com/questions/21951497
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