blocks|key|2975511|text|我找到了一个解决办法，但我需要在整个项目中注释每个日期的setter。有没有一种方法可以在创建ObjectMapper时指定格式？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2975512|下面是我所做的：|2975513|public+class+CustomJsonDateDeserializer+extends+JsonDeserializer<Date>
{
++++@Override
++++public+Date+deserialize(JsonParser+jsonParser,
++++++++++++DeserializationContext+deserializationContext)+throws+IOException,+JsonProcessingException+{

++++++++SimpleDateFormat+format+=+new+SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
++++++++String+date+=+jsonParser.getText();
++++++++try+{
++++++++++++return+format.parse(date);
++++++++}+catch+(ParseException+e)+{
++++++++++++throw+new+RuntimeException(e);
++++++++}

++++}

}|code-block|syntax|javascript|2975514|并使用下面的代码注释每个日期字段的setter方法：|2975515|@JsonDeserialize(using+=+CustomJsonDateDeserializer.class)|2975516|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I found a work around but with this I'll need to annotate each date's setter throughout the project. Is there a way in which I can specify the format while creating the ObjectMapper?

Here's what I did:

<pre><code>public class CustomJsonDateDeserializer extends JsonDeserializer&lt;Date&gt;
{
 @Override
 public Date deserialize(JsonParser jsonParser,
 DeserializationContext deserializationContext) throws IOException, JsonProcessingException {

 SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
 String date = jsonParser.getText();
 try {
 return format.parse(date);
 } catch (ParseException e) {
 throw new RuntimeException(e);
 }

 }

}
</code></pre>

And annotated each Date field's setter method with this:

<pre><code>@JsonDeserialize(using = CustomJsonDateDeserializer.class)
</code></pre>

blocks|key|273060|text|这对我很有效--我使用的是jackson+2.0.4|type|unstyled|depth|inlineStyleRanges|entityRanges|data|273061|ObjectMapper+objectMapper+=+new+ObjectMapper();
final+DateFormat+df+=+new+SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
objectMapper.setDateFormat(df);|code-block|syntax|javascript|273062|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This works for me - i am using jackson 2.0.4

<pre><code>ObjectMapper objectMapper = new ObjectMapper();
final DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
objectMapper.setDateFormat(df);
</code></pre>

blocks|key|271109|text|除了Varun+Achar's+answer之外，这是我想出的Java8变体，它使用java.time.LocalDate和ZonedDateTime而不是旧的java.util.Date类。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|271110|public+class+LocalDateDeserializer+extends+JsonDeserializer<LocalDate>+{

++++@Override
++++public+LocalDate+deserialize(JsonParser+jsonparser,+DeserializationContext+deserializationcontext)+throws+IOException+{

++++++++String+string+=+jsonparser.getText();

++++++++if(string.length()+>+20)+{
++++++++++++ZonedDateTime+zonedDateTime+=+ZonedDateTime.parse(string);
++++++++++++return+zonedDateTime.toLocalDate();
++++++++}

++++++++return+LocalDate.parse(string);
++++}
++}|code-block|syntax|javascript|271111|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/5598277/60518^0|2|K|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

In addition to <a href="https://stackoverflow.com/a/5598277/60518">Varun Achar's answer</a>, this is the Java 8 variant I came up with, that uses java.time.LocalDate and ZonedDateTime instead of the old java.util.Date classes.

<pre><code>public class LocalDateDeserializer extends JsonDeserializer&lt;LocalDate&gt; {

 @Override
 public LocalDate deserialize(JsonParser jsonparser, DeserializationContext deserializationcontext) throws IOException {

 String string = jsonparser.getText();

 if(string.length() &gt; 20) {
 ZonedDateTime zonedDateTime = ZonedDateTime.parse(string);
 return zonedDateTime.toLocalDate();
 }

 return LocalDate.parse(string);
 }
 }
</code></pre>

blocks|key|2975612|text|关于这个话题有一个很好的博客：http://www.baeldung.com/jackson-serialize-dates使用@JsonFormat看起来是最简单的方式。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2975613|public+class+Event+{
++++public+String+name;

++++@JsonFormat
++++++(shape+=+JsonFormat.Shape.STRING,+pattern+=+"dd-MM-yyyy+hh:mm:ss")
++++public+Date+eventDate;
}|code-block|syntax|javascript|2975614|entityMap|0|LINK|mutability|MUTABLE|url|http://www.baeldung.com/jackson-serialize-dates^0|F|1B|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

There is a good blog about this topic:
<a href="http://www.baeldung.com/jackson-serialize-dates" rel="noreferrer">http://www.baeldung.com/jackson-serialize-dates</a> 
Use @JsonFormat looks the most simple way.

<pre><code>public class Event {
 public String name;

 @JsonFormat
 (shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy hh:mm:ss")
 public Date eventDate;
}
</code></pre>

blocks|key|2975656|text|@JsonFormat仅适用于您正在使用的jackson版本支持的标准格式。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2975657|示例:-兼容jackson+2.8.6的任何标准格式("+yyyy+-MM-+dd+'T'HH:mm:ss.SSSZ"，"yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"，"EEE，dd+MMM+yyyy+HH:mm:ss+zzz"，“yyyy-MM-dd”)|2975658|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

@JsonFormat only work for standard format supported by the jackson version that you are using.

Ex :- compatible with any of standard forms ("yyyy-MM-dd'T'HH:mm:ss.SSSZ", "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", "EEE, dd MMM yyyy HH:mm:ss zzz", "yyyy-MM-dd")) for jackson 2.8.6

I'm getting a date string from ExtJS in the format: 

<blockquote>
 "2011-04-08T09:00:00"
</blockquote>

when i try to deserialize this date, it changes the timezone to Indian Standard Time (adds +5:30 to the time) . This is how i'm deserializing the date:

<pre><code>SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
getObjectMapper().getDeserializationConfig().setDateFormat(dateFormat);
</code></pre>

Doing this also doesn't change the timezone. I still get the date in IST:

<pre><code>SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
dateFormat.setTimeZone(TimeZone.getTimeZone("GMT"));
getObjectMapper().getDeserializationConfig().setDateFormat(dateFormat);
</code></pre>

How do I deserialize the date in the way in which it is coming without the hassles of Timezone?

How to deserialize JS date using Jackson?

我从ExtJS获得了一个日期字符串，格式如下： "2011-04-08T09:00:00“当我尝试反序列化此日期时，它将时区更改为印度标准时间(将时间增加+5:30 )。下面是我反序列化日期的方法：SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-d...

问如何使用Jackson反序列化JS date？
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