如何更新现有联系人？
如何更新现有联系人？
提问于 2011-12-13 21:34:57
我有一个现有的联系人，我需要添加一个工作地址到该现有联系人。我正在使用以下代码，但它不起作用。
String selectPhone = Data.CONTACT_ID + "=? AND " + Data.MIMETYPE + "='" +
ContactsContract.CommonDataKinds.StructuredPostal.CONTENT_ITEM_TYPE +
"'" + " AND " + ContactsContract.CommonDataKinds.StructuredPostal.TYPE + "=?";
String[] phoneArgs = new String[]
{String.valueOf(ContactId), String.valueOf(
ContactsContract.CommonDataKinds.StructuredPostal.TYPE_WORK)};
ops.add(ContentProviderOperation.newUpdate(Data.CONTENT_URI)
.withSelection(selectPhone, phoneArgs)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.STREET, STREET)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.CITY, CITY)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.REGION, REGION)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.POSTCODE, POSTCODE)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.COUNTRY, COUNTRY)
.build());
this.context.getContentResolver().applyBatch(ContactsContract.AUTHORITY, ops); 有什么解决方案吗？
回答 5
Stack Overflow用户
发布于 2012-02-21 12:18:50
/**
* @param name name of the contact
* @param number mobile phone number of contact
* @param email work email address of contact
* @param ContactId id of the contact which you want to update
* @return true if contact is updated successfully<br/>
* false if contact is not updated <br/>
* false if phone number contains any characters(It should contain only digits)<br/>
* false if email Address is invalid <br/><br/>
*
* You can pass any one among the 3 parameters to update a contact.Passing all three parameters as <b>null</b> will not update the contact
* <br/><br/><b>Note: </b>This method requires permission <b>android.permission.WRITE_CONTACTS</b><br/>
*/
public boolean updateContact(String name, String number, String email,String ContactId)
{
boolean success = true;
String phnumexp = "^[0-9]*$";
try
{
name = name.trim();
email = email.trim();
number = number.trim();
if(name.equals("")&&number.equals("")&&email.equals(""))
{
success = false;
}
else if((!number.equals(""))&& (!match(number,phnumexp)) )
{
success = false;
}
else if( (!email.equals("")) && (!isEmailValid(email)) )
{
success = false;
}
else
{
ContentResolver contentResolver = activity.getContentResolver();
String where = ContactsContract.Data.CONTACT_ID + " = ? AND " + ContactsContract.Data.MIMETYPE + " = ?";
String[] emailParams = new String[]{ContactId, ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE};
String[] nameParams = new String[]{ContactId, ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE};
String[] numberParams = new String[]{ContactId, ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE};
ArrayList<android.content.ContentProviderOperation> ops = new ArrayList<android.content.ContentProviderOperation>();
if(!email.equals(""))
{
ops.add(android.content.ContentProviderOperation.newUpdate(android.provider.ContactsContract.Data.CONTENT_URI)
.withSelection(where,emailParams)
.withValue(Email.DATA, email)
.build());
}
if(!name.equals(""))
{
ops.add(android.content.ContentProviderOperation.newUpdate(android.provider.ContactsContract.Data.CONTENT_URI)
.withSelection(where,nameParams)
.withValue(StructuredName.DISPLAY_NAME, name)
.build());
}
if(!number.equals(""))
{
ops.add(android.content.ContentProviderOperation.newUpdate(android.provider.ContactsContract.Data.CONTENT_URI)
.withSelection(where,numberParams)
.withValue(Phone.NUMBER, number)
.build());
}
contentResolver.applyBatch(ContactsContract.AUTHORITY, ops);
}
}
catch (Exception e)
{
e.printStackTrace();
success = false;
}
return success;
}
// To get COntact Ids of all contact use the below method
/**
* @return arraylist containing id's of all contacts <br/>
* empty arraylist if no contacts exist <br/><br/>
* <b>Note: </b>This method requires permission <b>android.permission.READ_CONTACTS</b>
*/
public ArrayList<String> getAllConactIds()
{
ArrayList<String> contactList = new ArrayList<String>();
Cursor cursor = activity.managedQuery(ContactsContract.Contacts.CONTENT_URI, null, null, null, "display_name ASC");
if (cursor != null)
{
if (cursor.moveToFirst())
{
do
{
int _id = cursor.getInt(cursor.getColumnIndex("_id"));
contactList.add(""+_id);
}
while(cursor.moveToNext());
}
}
return contactList;
}
private boolean isEmailValid(String email)
{
String emailAddress = email.toString().trim();
if (emailAddress == null)
return false;
else if (emailAddress.equals(""))
return false;
else if (emailAddress.length() <= 6)
return false;
else {
String expression = "^[a-z][a-z|0-9|]*([_][a-z|0-9]+)*([.][a-z|0-9]+([_][a-z|0-9]+)*)?@[a-z][a-z|0-9|]*\\.([a-z][a-z|0-9]*(\\.[a-z][a-z|0-9]*)?)$";
CharSequence inputStr = emailAddress;
Pattern pattern = Pattern.compile(expression,
Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(inputStr);
if (matcher.matches())
return true;
else
return false;
}
}
private boolean match(String stringToCompare,String regularExpression)
{
boolean success = false;
Pattern pattern = Pattern.compile(regularExpression);
Matcher matcher = pattern.matcher(stringToCompare);
if(matcher.matches())
success =true;
return success;
}Stack Overflow用户
发布于 2012-02-16 13:09:38
多亏了这个How to modify existing Contact，我终于找到了合适的solution..Much
秘诀在于您必须为.withSelection传递两个值，如下所示：
.withSelection(Data.RAW_CONTACT_ID + " = ?", new String[] {String.valueOf(id)})
.withSelection(Data._ID + " = ?", new String[] {mDataId})其中，by Data._ID value mDataId是这样获得的：
Cursor mDataCursor = this.context.getContentResolver().query(
Data.CONTENT_URI,
null,
Data.RAW_CONTACT_ID + " = ? AND " + Data.MIMETYPE + " = ?",
new String[] { String.valueOf(id), ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE},
null);
if(mDataCursor.getCount() > 0) {
mDataCursor.moveToFirst();
mDataId = getCursorString(mDataCursor, Data._ID);
MLog.v("Data", "Found data item with MIMETYPE");
mDataCursor.close();
} else {
MLog.v("Data", "Data doesn't contain MIMETYPE");
result = ERROR;
mDataCursor.close();
} getCursorString方法类似于：
private static String getCursorString(Cursor cursor, String columnName) {
int index = cursor.getColumnIndex(columnName);
if(index != -1) return cursor.getString(index);
return null;
}这是唯一的诀窍..
Stack Overflow用户
发布于 2012-02-17 21:50:43
每个字段(电子邮件、姓名、地址)都有自己的mime类型，您应该使用它来更新字段。
我们将使用数据表，其中每个Data.RAW_CONTACT_ID表示一些联系人的详细信息。
因此，我们需要找到Data.RAW_CONTACT_ID，其中id是您要编辑的联系人的id。
我希望这段代码能对你有所帮助。
String selectPhone = Data.RAW_CONTACT_ID + "=? AND " + Data.MIMETYPE + "='" +
ContactsContract.CommonDataKinds.StructuredPostal.CONTENT_ITEM_TYPE + "'" ;
String[] phoneArgs = new String[]{String.valueOf(rawContactId)};
ops.add(ContentProviderOperation.newUpdate(Data.CONTENT_URI)
.withSelection(selectPhone, phoneArgs)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.TYPE, ContactsContract.CommonDataKinds.StructuredPostal.TYPE_WORK)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.STREET, STREET)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.CITY, CITY)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.REGION, REGION)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.POSTCODE, POSTCODE)
.withValue(ContactsContract.CommonDataKinds.StructuredPostal.COUNTRY, POSTCODE)
.build());
this.context.getContentResolver().applyBatch(ContactsContract.AUTHORITY, ops);如果已经创建了一个新联系人，但没有地址，现在您想要向该联系人添加一个地址。在本例中，使用与上面相同的查询，但只需将newUpdate更改为newInsert，因为这样的行还不存在。
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原文链接：
https://stackoverflow.com/questions/8490123
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