首页
学习
活动
专区
工具
TVP
发布
社区首页 >问答首页 >字符串插值与拼接

字符串插值与拼接
EN

Stack Overflow用户
提问于 2013-12-07 22:04:12
回答 1查看 6.7K关注 0票数 21

在scala中构建字符串时,字符串插值是否比连接更有效?例如:

代码语言:javascript
复制
val myVal = "def"
val test = s"abs${myVal}ghi"

vs

代码语言:javascript
复制
val test = "abc" + myVal + "ghi"

我之所以这样问,是因为我需要为class编写toString方法,它有很多参数,因此插入的字符串会变得非常长且令人困惑,我想把它分成多行,但担心如果我连接它,它的性能会很差。

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2013-12-07 23:42:11

我举了一个简单的例子:

代码语言:javascript
复制
class Employee(name: String, age: Int) {
  private var s = 0.0
  def salary = s
  def salary_=(s: Double) = this.s = s
  def toStringConcat(): String = {
    "Name: " + name + ", age: " + age + ", salary: " + salary
  }
  def toStringInterpol(): String = {
    s"Name: $name, age: $age, salary: $salary"
  }
}

object Program {
  val empl = new Employee("John", 30)
  empl.salary = 10.50
  val times = 10000000;

  def main(args: Array[String]): Unit = {
    // warming-up
    val resultConcat = empl.toStringConcat
    val resultInterpol = empl.toStringInterpol
    println("Concat -> " + resultConcat)
    println("Interpol -> " + resultInterpol)

    val secondsConcat0 = run(empl.toStringConcat)
    val secondsInterpol0 = run(empl.toStringInterpol)
    val secondsConcat1 = run(empl.toStringConcat)
    val secondsInterpol1 = run(empl.toStringInterpol)

    println("Concat-0: " + secondsConcat0 + "s")
    println("Concat-1: " + secondsConcat1 + "s")
    println("Interpol-0: " + secondsInterpol0 + "s")
    println("Interpol-1: " + secondsInterpol1 + "s")
  }

  def run(call: () => String): Double = {
    val time0 = System.nanoTime()
    var result = ""
    for (i <- 0 until times) {
      result = call()
    }
    val time1 = System.nanoTime()

    val elapsedTime = time1 - time0;
    val seconds = elapsedTime / 1000000000.0;
    seconds
  }
}

结果如下:

代码语言:javascript
复制
Concat -> Name: John, age: 30, salary: 10.5
Interpol -> Name: John, age: 30, salary: 10.5
Concat-0: 2.831298161s
Concat-1: 2.725815448s
Interpol-0: 3.846891864s
Interpol-1: 3.753401004s

插值情况较慢。原因可以在生成的代码中找到:

代码语言:javascript
复制
  public String toStringConcat()
  {
    return new StringBuilder().append("Name: ").append(this.name).append(", age: ").append(BoxesRunTime.boxToInteger(this.age)).append(", salary: ").append(BoxesRunTime.boxToDouble(salary())).toString();
  }

  public String toStringInterpol()
  {
    return new StringContext(Predef..MODULE$.wrapRefArray((Object[])new String[] { "Name: ", ", age: ", ", salary: ", "" })).s(Predef..MODULE$.genericWrapArray(new Object[] { this.name, BoxesRunTime.boxToInteger(this.age), BoxesRunTime.boxToDouble(salary()) }));
  }

我使用的是Scala 2.10.3和IntelliJ IDEA 13。

票数 16
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/20442244

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档