blocks|key|4288951|text|你是说像这样的东西吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4288952|library(tidyverse);
df+%25>%25
++++group_by(gr)+%25>%25
++++mutate(numbering+=+cumsum(c(1,+diff(x)+!=+0)))
##+A+tibble:+16+x+3
##+Groups:+++gr+[2]
#+++++++x+gr+++numbering
#+++<int>+<fct>++++<dbl>
#+1+++++0+1+++++++++++1.
#+2+++++0+1+++++++++++1.
#+3+++++1+1+++++++++++2.
#+4+++++1+1+++++++++++2.
#+5+++++2+1+++++++++++3.
#+6+++++2+1+++++++++++3.
#+7+++++3+1+++++++++++4.
#+8+++++3+1+++++++++++4.
#+9+++++0+2+++++++++++1.
#10+++++0+2+++++++++++1.
#11+++++1+2+++++++++++2.
#12+++++1+2+++++++++++2.
#13+++++2+2+++++++++++3.
#14+++++2+2+++++++++++3.
#15+++++3+2+++++++++++4.
#16+++++3+2+++++++++++4.|code-block|syntax|javascript|4288953|或者，如果您必须使用numbering+sequence+2,4,6,...而不是1,2,3,...，您可以这样做|offset|length|style|CODE|4288954|df+%25>%25
++++group_by(gr)+%25>%25
++++mutate(numering+=+2+*+cumsum(c(1,+diff(x)+!=+0)));
##+A+tibble:+16+x+3
##+Groups:+++gr+[2]
#+++++++x+gr++++numering
#+++<int>+<fct>++++<dbl>
#+1+++++0+1+++++++++++2.
#+2+++++0+1+++++++++++2.
#+3+++++1+1+++++++++++4.
#+4+++++1+1+++++++++++4.
#+5+++++2+1+++++++++++6.
#+6+++++2+1+++++++++++6.
#+7+++++3+1+++++++++++8.
#+8+++++3+1+++++++++++8.
#+9+++++0+2+++++++++++2.
#10+++++0+2+++++++++++2.
#11+++++1+2+++++++++++4.
#12+++++1+2+++++++++++4.
#13+++++2+2+++++++++++6.
#14+++++2+2+++++++++++6.
#15+++++3+2+++++++++++8.
#16+++++3+2+++++++++++8.|4288955|entityMap^0|0|0|A|9|T|9|15|9|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]|$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|P|$]]

Do you mean something like this?

<pre><code>library(tidyverse);
df %&gt;%
 group_by(gr) %&gt;%
 mutate(numbering = cumsum(c(1, diff(x) != 0)))
## A tibble: 16 x 3
## Groups: gr [2]
# x gr numbering
# &lt;int&gt; &lt;fct&gt; &lt;dbl&gt;
# 1 0 1 1.
# 2 0 1 1.
# 3 1 1 2.
# 4 1 1 2.
# 5 2 1 3.
# 6 2 1 3.
# 7 3 1 4.
# 8 3 1 4.
# 9 0 2 1.
#10 0 2 1.
#11 1 2 2.
#12 1 2 2.
#13 2 2 3.
#14 2 2 3.
#15 3 2 4.
#16 3 2 4.
</code></pre>

Or if you must have a <code>numbering</code> sequence <code>2,4,6,...</code> instead of <code>1,2,3,...</code> you can do

<pre><code>df %&gt;%
 group_by(gr) %&gt;%
 mutate(numering = 2 * cumsum(c(1, diff(x) != 0)));
## A tibble: 16 x 3
## Groups: gr [2]
# x gr numering
# &lt;int&gt; &lt;fct&gt; &lt;dbl&gt;
# 1 0 1 2.
# 2 0 1 2.
# 3 1 1 4.
# 4 1 1 4.
# 5 2 1 6.
# 6 2 1 6.
# 7 3 1 8.
# 8 3 1 8.
# 9 0 2 2.
#10 0 2 2.
#11 1 2 4.
#12 1 2 4.
#13 2 2 6.
#14 2 2 6.
#15 3 2 8.
#16 3 2 8.
</code></pre>

blocks|key|4288976|text|下面是一个选项，使用match获取索引，然后传递要填充的seq值|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4288977|df+%25>%25+
+++group_by(gr)+%25>%25
+++mutate(numbering+=+seq(2,+length.out+=+n()/2,+by+=+2)[match(x,+unique(x))])
#+A+tibble:+16+x+3
#+Groups:+++gr+[2]
#+++++++x+gr++++numbering
#+++<int>+<fct>+++++<dbl>
#+1+++++0+1+++++++++++++2
#+2+++++0+1+++++++++++++2
#+3+++++1+1+++++++++++++4
#+4+++++1+1+++++++++++++4
#+5+++++2+1+++++++++++++6
#+6+++++2+1+++++++++++++6
#+7+++++3+1+++++++++++++8
#+8+++++3+1+++++++++++++8
#+9+++++0+2+++++++++++++2
#10+++++0+2+++++++++++++2
#11+++++1+2+++++++++++++4
#12+++++1+2+++++++++++++4
#13+++++2+2+++++++++++++6
#14+++++2+2+++++++++++++6
#15+++++3+2+++++++++++++8
#16+++++3+2+++++++++++++8|code-block|syntax|javascript|4288978|entityMap^0|A|5|S|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

Here is an option using <code>match</code> to get the index and then pass on the <code>seq</code> values to fill 

<pre><code>df %&gt;% 
 group_by(gr) %&gt;%
 mutate(numbering = seq(2, length.out = n()/2, by = 2)[match(x, unique(x))])
# A tibble: 16 x 3
# Groups: gr [2]
# x gr numbering
# &lt;int&gt; &lt;fct&gt; &lt;dbl&gt;
# 1 0 1 2
# 2 0 1 2
# 3 1 1 4
# 4 1 1 4
# 5 2 1 6
# 6 2 1 6
# 7 3 1 8
# 8 3 1 8
# 9 0 2 2
#10 0 2 2
#11 1 2 4
#12 1 2 4
#13 2 2 6
#14 2 2 6
#15 3 2 8
#16 3 2 8
</code></pre>

Hi I have a data frame like this

<pre><code>df &lt;-data.frame(x=rep(rep(seq(0,3),each=2),2 ),gr=gl(2,8))

 x gr
1 0 1
2 0 1
3 1 1
4 1 1
5 2 1
6 2 1
7 3 1
8 3 1
9 0 2
10 0 2
11 1 2
12 1 2
13 2 2
14 2 2
15 3 2
16 3 2
</code></pre>

I want to add a new column <code>numbering</code> sequence of numbers when the <code>x</code> value <code>==0</code>

I tried 

<pre><code>library(dplyr)
df%&gt;%
 group_by(gr)%&gt;%
 mutate(numbering=seq(2,8,2))

Error in mutate_impl(.data, dots) : 
 Column `numbering` must be length 8 (the group size) or one, not 4
</code></pre>

?

Just for side note <code>mutate(numbering=rep(seq(2,8,2),each=2))</code> would work for this minimal example but for the general case its better to look x value change from 0! 

the expected output

<pre><code> x gr numbering
1 0 1 2
2 0 1 2
3 1 1 4
4 1 1 4 
5 2 1 6
6 2 1 6
7 3 1 8
8 3 1 8
9 0 2 2
10 0 2 2
11 1 2 4
12 1 2 4
13 2 2 6
14 2 2 6
15 3 2 8
16 3 2 8
</code></pre>

Adding sequence of numbers to the data

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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嗨，我有一个像这样的数据框df <-data.frame(x=rep(rep(seq(0,3),each=2),2 ),gr=gl(2,8)) x gr1 0 12 0 13 1 14 1 15 2 16 2 17 3 18 3 19 0 ...

问将数字序列添加到数据中
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