PHP从对象中删除空项
PHP从对象中删除空项
提问于 2018-05-05 01:17:34
我有以下对象，在这里打印为数组。此对象是从SOAP请求构建的。
AdminInfo Object (
[Supplier] => Supplier Object (
[Party] => Party Object (
[OrgInfo] => OrgInfo Object (
[CompanyName] => Bobs
[IDInfo] => Array of IDInfo Objects (
[0] => IDInfo Object (
[IDQualifierCode] =>
[IDNum] =>
)
[1] => IDInfo Object (
[IDQualifierCode] => CompanyID
[IDNum] => 83e26599-d40g-4cba-9791-7d7c83de282c
)
[2] => IDInfo Object (
[IDQualifierCode] => TID
[IDNum] => BOBTID01020304
)
[3] => IDInfo Object (
[IDQualifierCode] => Token
[IDNum] => c784570e-044d-42c8-98fe-af9f7c1747f5
)
)
)
[ContactInfo] => ContactInfo Object (
[ContactJobTitle] =>
[Communications] => Comm Object (
[CommQualifier] =>
[CommPhone] =>
[CommEmail] =>
[Address] => Address Object (
[Address1] =>
[Address2] =>
[City] =>
[StateProvince] =>
[PostalCode] =>
[CountryCode] =>
)
)
[ContactName] => PersonName Object (
[FirstName] =>
[MiddleName] =>
[LastName] =>
)
)
)
)
[Company] => Company Object (
[Party] => Party Object (
[OrgInfo] => OrgInfo Object (
[CompanyName] => SF
[IDInfo] =>
)
[ContactInfo] =>
)
)
[Facility] => Facility Object (
[Party] => Party Object (
[OrgInfo] => Array of OrgInfo Objects (
)
[ContactInfo] => ContactInfo Object (
[ContactJobTitle] => Owner
[Communications] => Array of Comm Objects(
[0] => Comm Object (
[CommQualifier] => WP
[CommPhone] => 1234567890
)
[1] => Comm Object (
[CommQualifier] => SA
[Address] => Address Object (
[Address1] => 123 NE 14th St
[City] => Nowhere
[StateProvince] => ND
[PostalCode] => 12345
[CountryCode] => US
)
)
[2] =>
[3] =>
)
[ContactName] => PersonName Object (
[FirstName] => Bob
[MiddleName] =>
[LastName] => Tester
)
)
)
)
)我想要做的是删除所有的空元素，并随此对象一起返回
AdminInfo Object (
[Supplier] => Supplier Object (
[Party] => Party Object (
[OrgInfo] => OrgInfo Object (
[CompanyName] => Bobs
[IDInfo] => Array of IDInfo Objects (
[0] => IDInfo Object (
[IDQualifierCode] =>
[IDNum] =>
)
[1] => IDInfo Object (
[IDQualifierCode] => CompanyID
[IDNum] => 83e26599-d40g-4cba-9791-7d7c83de282c
)
[2] => IDInfo Object (
[IDQualifierCode] => TID
[IDNum] => BOBTID01020304
)
[3] => IDInfo Object (
[IDQualifierCode] => Token
[IDNum] => c784570e-044d-42c8-98fe-af9f7c1747f5
)
)
)
)
)
[Company] => Company Object (
[Party] => Party Object (
[OrgInfo] => OrgInfo Object (
[CompanyName] => SF
)
)
)
[Facility] => Facility Object (
[Party] => Party Object (
[ContactInfo] => ContactInfo Object (
[ContactJobTitle] => Owner
[Communications] => Array of Comm Objects (
[0] => Comm Object (
[CommQualifier] => WP
[CommPhone] => 1234567890
)
[1] => Comm Object (
[CommQualifier] => SA
[Address] => Address Object (
[Address1] => 123 NE 14th St
[City] => Nowhere
[StateProvince] => ND
[PostalCode] => 12345
[CountryCode] => US
)
)
)
[ContactName] => PersonName Object (
[FirstName] => Bob
[LastName] => Tester
)
)
)
)
)这些尝试根本没有做到这一点；变量$AdminInfo是上面的对象...
来自此处的解决方案：strip null values of json object
$json = json_encode($AdminInfo);
$result = preg_replace('/,\s*"[^"]+":null|"[^"]+":null,?/', '', $json);
$echo $result;来自此处的解决方案：How to remove null values from an array?
$json = json_encode($AdminInfo); // convert to JSON
$arr = (array)json_decode($json); // convert to an array
$object = (object) array_filter((array) $arr); // filter the array
$result = json_encode($object); // convert it back to JSON
echo $result;从这里：PHP - How to remove empty entries of an array recursively?
function array_remove_empty($haystack)
{
foreach ($haystack as $key => $value) {
if (is_array($value)) {
$haystack[$key] = array_remove_empty($haystack[$key]);
}
if (empty($value)) {
unset($haystack[$key]);
}
}
return $haystack;
}
$json = json_encode($AdminInfo); // convert to JSON
$arr = (array)json_decode($json); // convert to an array
print_r(array_remove_empty($arr)); // run through array_remove_empty function and print来自此处的解决方案：Remove items from multidimensional array in PHP
function cleanArray($array) {
if (is_array($array)) {
foreach ($array as $key => $sub_array)
{
$result = cleanArray($sub_array);
if ($result === false) {
unset($array[$key]);
} else {
$array[$key] = $result;
}
}
}
if (empty($array)) {
return false;
}
return $array;
}
$json = json_encode($AdminInfo); // convert to JSON
$arr = (array)json_decode($json); // convert to an array
print_r(cleanArray($arr)); // run through cleanArray function and print编辑
作为JSON的AdminInfo对象：
{
"Supplier":{
"Party":{
"OrgInfo":{
"CompanyName":"Bobs",
"IDInfo":[
{
"IDQualifierCode":null,
"IDNum":""
},
{
"IDQualifierCode":"CompanyID",
"IDNum":"83e26599-d40g-4cba-9791-7d7c83de282c"
},
{
"IDQualifierCode":"TID",
"IDNum":"BOBTID01020304"
},
{
"IDQualifierCode":"Token",
"IDNum":"c784570e-044d-42c8-98fe-af9f7c1747f5"
}
]
},
"ContactInfo":{
"ContactJobTitle":"",
"Communications":{
"CommQualifier":null,
"CommPhone":"",
"CommEmail":"",
"Address":{
"Address1":"",
"Address2":"",
"City":"",
"StateProvince":null,
"PostalCode":"",
"CountryCode":null
}
},
"ContactName":{
"FirstName":"",
"MiddleName":"",
"LastName":""
}
}
}
},
"Company":{
"Party":{
"OrgInfo":{
"CompanyName":"SF",
"IDInfo":null
},
"ContactInfo":null
}
},
"Facility":{
"Party":{
"OrgInfo":[
],
"ContactInfo":{
"ContactJobTitle":"",
"Communications":[
{
"CommQualifier":null,
"CommPhone":"",
"CommEmail":"",
"Address":{
"Address1":"",
"Address2":"",
"City":"",
"StateProvince":null,
"PostalCode":"",
"CountryCode":null
}
},
null,
null,
null
],
"ContactName":{
"FirstName":"Bob",
"MiddleName":"",
"LastName":"Tester"
}
}
}
}
}回答 3
Stack Overflow用户
回答已采纳
发布于 2018-05-06 07:31:04
要求:递归扫描嵌套数组，剪除空的分支/项。
这是另一种“树上漫步”。
唯一“棘手”的部分是让树上更高的处理知道是否将当前项添加到输出树中。
处理节点的函数将返回一个数组，该数组具有'keep value‘标志以及要保留的值。
JSON Converted to array: Full Working code at eval.in
Output preserves original JSON Data Type: Full Working code at eval.in
代码：
function processList(array $list)
{
$listResult = ['keepValue' => false, // once set true will propagate upward
'value' => []];
foreach ($list as $name => $item ) {
if (is_null($item)) { // see is_scalar test
continue;
}
if (is_scalar($item)) { // keep the value?
if (!empty($item) || strlen(trim($item)) > 0) {
$listResult['keepValue'] = true;
$listResult['value'][$name] = $item;
}
} else { // new list... recurse
$itemResult = processList($item);
if ($itemResult['keepValue']) {
$listResult['keepValue'] = true;
$listResult['value'][$name] = $itemResult['value'];
}
}
}
return $listResult;
} 运行函数：
$source = json_decode($json, true);
$result = processList($source);
print_r($result['value']);输出：
Array
(
[Supplier] => Array
(
[Party] => Array
(
[OrgInfo] => Array
(
[CompanyName] => Bobs
[IDInfo] => Array
(
[1] => Array
(
[IDQualifierCode] => CompanyID
[IDNum] => 83e26599-d40g-4cba-9791-7d7c83de282c
)
[2] => Array
(
[IDQualifierCode] => TID
[IDNum] => BOBTID01020304
)
[3] => Array
(
[IDQualifierCode] => Token
[IDNum] => c784570e-044d-42c8-98fe-af9f7c1747f5
)
)
)
)
)
[Company] => Array
(
[Party] => Array
(
[OrgInfo] => Array
(
[CompanyName] => SF
)
)
)
[Facility] => Array
(
[Party] => Array
(
[ContactInfo] => Array
(
[ContactName] => Array
(
[FirstName] => Bob
[LastName] => Tester
)
)
)
)
)Stack Overflow用户
发布于 2018-05-05 03:42:06
在经历了一些困惑之后，我想出了一个递归函数，就像我之前建议的那样，它将对象转换为一个数组，以检查变量是否设置为null。
如果该对象内的所有变量都为空，则对父对象进行索引以将该对象的引用设置为空。
我尽我所能地解释和记录代码。
请不要只是复制代码并完成它，而是通过阅读它，并尝试从我提供的代码中学习。
/**
Unsets all empty variables in $object
*/
function loopTrough(&$object, &$parent = null, $key = null, $objectIsArray = false, $parentIsArray = false)
{
// Keep track of amount of vars and amount of null vars
$vars = 0;
$null = 0;
foreach($object as $index => $value)
{
$vars = $vars + 1;
// Also check if is array
$isArray = is_array($value);
// Check if is object
if (is_object($value) || $isArray) // using value here is save
{
// Loop trough the new object (or array) we found
if ($objectIsArray)
{
loopTrough($object[$index], $object, $index, $isArray, $objectIsArray);
}
else
{
loopTrough($object->{$index}, $object, $index, $isArray, $objectIsArray);
}
}
// Check if is null
if ($objectIsArray)
{
if (!isset($object[$index]) || $object[$index] == ""){
$null = $null + 1;
// We don't want to show null
unset($object[$index]);
}
}
else
{
if (!isset($object->{$index}) || $object->{$index} == "") // use $object->{index} here, and not $value because $value does not change when object reference is changed
{
$null = $null + 1;
// We don't want to show null
unset($object->{$index});
}
}
}
// If there are as much null variables as variables
if ($vars == $null && $parent !== null && $key !== null)
{
// Set the parent reference to null
if ($parentIsArray) // Example exludes arrays, uncomment this if you want values in arrays to be recurisvely set to null
{
// unset($parent[$key]);
}
else
{
unset($parent->{$key});
}
}
}
class Test
{
public $one;
public $two;
}
$test = new Test();
$test->one = new Test();
$test->one->two = "On";
$test->two = new Test();
$test->two->one = new Test();
var_dump($test);
loopTrough($test);
var_dump($test);Stack Overflow用户
发布于 2018-05-05 02:59:37
正如我之前所建议的，您可以将object转换为array，并递归地循环遍历元素，以检查它们是否为null。
递归函数将非常复杂，因为您不仅要删除null变量，而且要删除所有包含null的变量。
下面是一个没有递归的示例，它只是从object中删除null变量
class A
{
public $var = "aVar";
public $var1 = null;
}
$a = new A();
var_dump($a);
$array = (array)$a;
foreach($array as $key => $value)
{
if (is_null($value)){
unset($array[$key]);
}
}
var_dump($array);页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50180118
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