在tweepy中无法使用计数器
在tweepy中无法使用计数器
提问于 2018-06-02 04:04:54
from tweepy import OAuthHandler
import tweepy
from tweepy import StreamListener
from tweepy import Stream
import time
consumer_key = 'super secret consumer key'
consumer_secret = 'shhhhh can't tell anyone this!'
access_token = 'hmmmmmmmmmmmmm'
access_secret = 'arrays should start at 0'
auth = OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_secret)
api = tweepy.API(auth)
print('')
print('starting...')
time.sleep(3)
class MySteamListener(tweepy.StreamListener):
def on_status(self, status):
#prints status text. can be replaced with a counter probably.
counter = counter + 1
print(status.text)
def on_error(self, status_code):
if status_code == 420:
print('420 error')
#Ends stream in case of rate limiting
return False
mySteamListener = MySteamListener()
myStream = tweepy.Stream(auth = api.auth, listener = mySteamListener)
myStream.filter(track = ['Warriors'])我是tweepy的新手，我要做的第一件事就是编写一个程序，扫描所有tweet中的特定单词。在我尝试为该单词添加一个实例数计数器之前，一切都运行得很好。无论我在哪里赋值计数器，我总是得到一个'UnboundLocalError: local variable ' counter‘赋值前引用’错误。在这个程序中我应该把计数器分配到哪里？
回答 1
Stack Overflow用户
回答已采纳
发布于 2018-06-02 04:20:46
假设上面的“不能”并不在你的代码中，如果可能的话，更新你的问题以省略"'“，因为它弄乱了可读性或更改为其他占位符文本。
如错误所示，您还没有为计数器赋值，方法"on_status“将尝试递增计数器，但这只是该方法的本地计数器，而不是对象，因此它失败了。
def on_status(self, status):
#prints status text. can be replaced with a counter probably.
counter = counter + 1
print(status.text)您应该在初始化方法中初始化计数器，然后改用self.counter。
添加
...
class MySteamListener(tweepy.StreamListener):
def __init__(self):
# Not sure if necessary, to make this work, but you could
# Initialize the inherited class as well (this may work only in Python 3)
# super().__init__()
self.counter = 0
...将on_status修改为
def on_status(self, status):
#prints status text. can be replaced with a counter probably.
self.counter = self.counter + 1
# Can be written as 'self.counter += 1'
print(status.text)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50650345
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