我有三个按钮,一个按钮被选中,第一个按钮被标记为X,第二个被选中的按钮将被标记为O,最后一个按钮再次被标记为X。
如果X被标记,那么它的颜色是白色,如果它是O,那么它被标记为灰色。
现在我想要做的是使用保存的实例,以便当我旋转手机时,颜色保持不变。实际发生的情况是,如果我旋转手机,那么做出的最新选择,所有文本都会恢复为该颜色。
因此,如果我按下X和O并旋转手机,X和O都将显示为灰色,这是O的颜色。
如果我选择最后一个X并旋转电话,所有的字母都将被标记为白色,这是X的颜色。
我不确定是设置的颜色导致了它,还是记住了谁移动了它之前是谁,并根据它设置颜色,我的问题是如何解决它,使所有的字母保持他们的颜色轮换?
private boolean playerOneMove = true;
private Button[][] buttons = new Button[1][3];
private static final String TEXT_COLOR = "textColor";
private String textColor;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main_player2);
btnObj1 = findViewById(R.id.button_00);
btnObj2 = findViewById(R.id.button_01);
btnObj3 = findViewById(R.id.button_02);
if (savedInstanceState != null) {
textColor = savedInstanceState.getString(TEXT_COLOR);
if(btnObj1 != null) {
btnObj1.setTextColor(Color.parseColor(textColor));
}
if (btnObj2 != null) {
btnObj2.setTextColor(Color.parseColor(textColor));
}
if (btnObj3 != null) {
btnObj3.setTextColor(Color.parseColor(textColor));
}
for (int i = 0; i < 1; i++) {
for (int j = 0; j < 3; j++) {
String buttonID = "button_" + i + j;
int resID = getResources().getIdentifier(buttonID, "id", getPackageName());
buttons[i][j] = findViewById(resID);
buttons[i][j].setOnClickListener(this);
}
}
}
@Override
public void onClick(View v) {
if (!((Button) v).getText().toString().equals("")) {
return;
}
if (playerOneMove) {
((Button) v).setText("X");
textColor = "#e8e5e5";
((Button) v).setTextColor(Color.parseColor(textColor));
} else {
((Button) v).setText("O");
textColor = "#737374";
((Button) v).setTextColor(Color.parseColor(textColor));
}
}
@Override
protected void onSaveInstanceState(Bundle outState) {
super.onSaveInstanceState(outState);
outState.putBoolean("playerOneMove", playerOneMove);
outState.putString(TEXT_COLOR, textColor);
}
@Override
protected void onRestoreInstanceState(Bundle savedInstanceState) { ;
super.onRestoreInstanceState(savedInstanceState);
playerOneMove = savedInstanceState.getBoolean("playerOneMove");
textColor = savedInstanceState.getString(TEXT_COLOR);
}
发布于 2018-06-05 02:59:13
你看到的行为是正常的,因为你保存了一个textColor,它将始终是用户最后设置的那个。相反,您可以简单地迭代按钮数组并保存每个按钮的文本颜色:
@Override
protected void onSaveInstanceState(Bundle outState) {
super.onSaveInstanceState(outState);
for (int i = 0; i < 1; i++) {
for (int j = 0; j < 3; j++) {
String buttonID = "button_" + i + j;
Button btn = buttons[i][j];
outState.putCharSequence(buttonID, btn.getText());
}
}
}
然后在onCreate()(移除onRestoreInstanceState()方法)中恢复按钮的状态:
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main_player2);
int playerX = Color.parseColor("#e8e5e5");
int playerO = Color.parseColor("#737374");
for (int i = 0; i < 1; i++) {
for (int j = 0; j < 3; j++) {
String buttonID = "button_" + i + j;
int resID = getResources().getIdentifier(buttonID, "id", getPackageName());
buttons[i][j] = findViewById(resID);
buttons[i][j].setOnClickListener(this);
if (savedInstanceState != null) {
String btnState = savedInstanceState.getCharSequence(buttonID);
if (btnState.equals("X")) {
// this is player X
buttons[i][j].setTextColor(playerX);
} else if (btnState.equals("O")) {
// this is player O
buttons[i][j].setTextColor(playerO);
} else {
// unclicked btn, do you have another color?
}
}
}
}
如果您有更多的按钮,则将按钮状态分组并保存在列表中可能更有意义,而不是保存单个按钮状态。
https://stackoverflow.com/questions/50685842
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