问如何在Python (asyncio)中创建一个可以在创建后启动的懒惰未来？

EN

import asyncio
from typing import (
    Awaitable,
    Any
)

class ThingThatWeAreWaitingOn():
    name = "Async Thingy"

class PeerPool():

    def __init__(self, discovery: Awaitable[ThingThatWeAreWaitingOn]):
        self.awaitable_discovery = discovery

    def do_stuff(self):
        print("Do stuff called")
        self.awaitable_discovery.add_done_callback(lambda d: print(d.result().name))

class Server():

    def __init__(self):
        # This immediately kicks of the async task but all I want is to 
        # create a Future to pass that would ideally be kicked off in
        # the run() method
        self.fut_discovery = asyncio.ensure_future(self.get_discovery())
        self.peer_pool = PeerPool(self.fut_discovery)
    
    async def get_discovery(self):
        await asyncio.sleep(1)
        return ThingThatWeAreWaitingOn()

    def run(self):
        loop = asyncio.get_event_loop()
        print("Server booting")

        # Here is where I want to "kick off" the self.fut_discovery but how?
        # self.fut_discovery.kick_off_now()

        self.peer_pool.do_stuff()

        loop.run_forever()

server = Server()
server.run()