document.getElementsByClassName不工作
document.getElementsByClassName不工作
提问于 2018-06-14 04:36:45
有人知道它为什么不工作吗？
当我点击div dotaz时，我想让它显示div odpoved。
function ukaz(a) {
var elements = document.getElementsByClassName(a);
for (var i = 0; i < elements.length; i++) {
elements[i].style.display = "block";
}
}<div class="dotaz" onClick="ukaz(odpoved)">
<p>YOSODJDN</p>
<span class="qanick">jirka</span>
<span class="fafadown"><i class="arrow fa fa-angle-down" style="font-size:24px"></i></span>
</div>
<div class="odpoved" style="display:none">
<p>ODPOVED</p>
<span class="qanick">anetka</span>
</div>
回答 2
Stack Overflow用户
发布于 2018-06-14 04:39:37
像这样使用它，将odpoved作为字符串传递
<div class="dotaz" onClick="ukaz('odpoved')">
<div class="dotaz" onClick="ukaz('odpoved')">
<p>YOSODJDN</p>
<span class="qanick">jirka</span>
<span class="fafadown"><i class="arrow fa fa-angle-down" style="font-
size:24px"></i></span>
</div>
<div class="odpoved" style="display:none">
<p>ODPOVED</p>
<span class="qanick">anetka</span>
</div>
<script>
function ukaz(a) {
var elements = document.getElementsByClassName(a);
for (var i = 0; i < elements.length; i++) {
elements[i].style.display = "block";
}
}
</script>
Stack Overflow用户
发布于 2018-06-14 04:42:50
onClick="ukaz(odpoved)"正在尝试调用函数，使用变量而不是字符串作为参数。
function ukaz(a) {
var elements = document.getElementsByClassName(a);
for (var i = 0; i < elements.length; i++) {
elements[i].style.display = "block";
}
}<div class="dotaz" onClick="ukaz('odpoved')"> <!-- odpoved is a string, not a variable -->
<p>YOSODJDN</p>
<span class="qanick">jirka</span>
<span class="fafadown">
<i class="arrow fa fa-angle-down" style="font-size:24px"></i>
</span>
</div>
<div class="odpoved" style="display:none">
<p>ODPOVED</p>
<span class="qanick">anetka</span>
</div>
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50845888
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