String rank[] = {"tclub1.png", "tclub2.png", "tclub3.png", "tclub4.png",
"tclub5.png", "tclub6.png", "tclub7.png", "tclub8.png", "tclub9.png",
"tclub10.png", "tclub11.png", "tclub12.png", "tclub13.png"};
Random randInt = new Random();
int b = randInt.nextInt(rank.length);
String d = ("tclub" + b + ".png");
Log.v(LOG_TAG, "in value:=" + d);
上面是代码。实际上,我的数组给了我一个介于(0到12)..after之间的随机索引,我将它附加到后面来生成一个图像名称。例如(tclub1.png)现在它给我的图像名称是字符串格式。我现在如何随机分配这个镜像?
发布于 2010-07-23 17:10:12
如果要将图像加载到ImageView,可以执行以下操作:
String imgName = "tclub1"; // the image you want to load
int id = getResources().getIdentifier(imgName, "drawable", getPackageName());
imageView.setImageResource(id);
发布于 2011-11-13 19:34:43
要查找控件,请执行以下操作:
ImageView image = (ImageView) findViewById(R.id.rockId);
为了从drawable中动态加载图像,我使用了这个helper函数
public static int getDrawable(Context context, String name)
{
Assert.assertNotNull(context);
Assert.assertNotNull(name);
return context.getResources().getIdentifier(name,
"drawable", context.getPackageName());
}
这将返回可绘制的id,现在您需要做的就是在控件中设置图像:
image.setImageResource(int Id);
https://stackoverflow.com/questions/3316768
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