如何用CSS链接到网页顶部和底部?

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有人能告诉我什么是创建链接的好方法吗?我网页中回到顶部的功能实现了,但到达底层的按钮有问题。

这是我尝试做的网页。(忽略到达底层按钮的图片即可):

<a href="#Top" name="Top" id="Top" class="cd-top cd-is-visible cd-fade-out" >Top</a>
<a href="#Bot" name="Bot" id="Bot" class="cd-bottom cd-is-visible cd-fade-out">Bottom</a>

这是我用的CSS:

/******************** Back to top and/or bottom ********************/
.cd-top {
  display: inline-block;
  height: 40px;
  width: 40px;
  position: fixed;
  top: 45%;
  right: 10px;
  box-shadow: 0 0 10px rgba(0, 0, 0, 0.05);
  /* image replacement properties */
  overflow: hidden;
  text-indent: 100%;
  white-space: nowrap;
  background: #03a400 url(images/cd-top-arrow.svg) no-repeat center 50%;
  visibility: hidden;
  opacity: 0;
  -webkit-transition: opacity .3s 0s, visibility 0s .3s;
  -moz-transition: opacity .3s 0s, visibility 0s .3s;
  transition: opacity .3s 0s, visibility 0s .3s;
}

.cd-top.cd-is-visible, .cd-top.cd-fade-out, .no-touch .cd-top:hover {
  -webkit-transition: opacity .3s 0s, visibility 0s 0s;
  -moz-transition: opacity .3s 0s, visibility 0s 0s;
  transition: opacity .3s 0s, visibility 0s 0s;
}
.cd-top.cd-is-visible {
  /* the button becomes visible */
  visibility: visible;
  opacity: 63;
}
.cd-top.cd-fade-out {
  /* if the user keeps scrolling down, the button is out of focus and becomes less visible */
  /*    opacity: .5; */
}
.cd-top:hover {
  background-color: #489148;
  opacity: 1;
}

.cd-bottom {
  display: inline-block;
  height: 40px;
  width: 40px;
  position: fixed;
  bottom: 45%;
  right: 10px;
  box-shadow: 0 0 10px rgba(0, 0, 0, 0.05);
  /* image replacement properties */
  overflow: hidden;
  text-indent: 100%;
  white-space: nowrap;
  background: #03a400 url(images/cd-bottom-arrow.png) no-repeat center 50%;
  visibility: hidden;
  opacity: 0;
  -webkit-transition: opacity .3s 0s, visibility 0s .3s;
  -moz-transition: opacity .3s 0s, visibility 0s .3s;
  transition: opacity .3s 0s, visibility 0s .3s;
}

下面是我用的Javascript:

;jQuery(document).ready(function($){
    // browser window scroll (in pixels) after which the "back to top" link is shown
    var offset = 300,
        //browser window scroll (in pixels) after which the "back to top" link opacity is reduced
        offset_opacity = 1200,
        //duration of the top scrolling animation (in ms)
        scroll_top_duration = 700,
        //grab the "back to top" link
        $back_to_top = $('.cd-top');

        //grab the "back to bottom" link
        $back_to_bottom = $('.cd-bottom');      

    //hide or show the "back to top" link
    $(window).scroll(function(){
        ( $(this).scrollTop() > offset ) ? $back_to_top.addClass('cd-is-visible') : $back_to_top.removeClass('cd-is-visible cd-fade-out');
        if( $(this).scrollTop() > offset_opacity ) {
            $back_to_top.addClass('cd-fade-out');
        }
    });

    //smooth scroll to top
    $back_to_top.on('click', function(event){
        event.preventDefault();
        $('body,html').animate({
            scrollTop: 0 ,
            }, scroll_top_duration
        );
    });

    //hide or show the "back to bottom" link
    $(window).scroll(function(){
        ( $(this).scrollBottom() > offset ) ? $back_to_bottom.addClass('cd-is-visible') : $back_to_bottom.removeClass('cd-is-visible cd-fade-out');
        if( $(this).scrollBottom() > offset_opacity ) {
            $back_to_bottom.addClass('cd-fade-out');
        }
    });

    //smooth scroll to bottom
    $back_to_bottom.on('click', function(event){
        event.preventDefault();
        $('body,html').animate({
            scrollTop: 0 ,
            }, scroll_top_duration
        );
    });

});

有人能告诉我哪里出错了吗?谢谢!

提问于
用户回答回答于

因为你将滚动顶部设置为0,所以单击按钮会不起作用。如果将其改到页面的高度,它就会正常工作。这是一个带有可滚动页面的更新代码:http://jsfiddle.net/twvn1z3s/7/


假设这是你的整个CSS。你需要对你的CSS做一些小调整。例如:

.cd-top.cd-is-visible你设置opacity/visibility,但不是对bottom按钮起作用。

修改成:

.cd-top.cd-is-visible,
.cd-bottom.cd-is-visible{
    /* the button becomes visible */
    visibility: visible;
    opacity: 1;
}

然后它就会出现。一旦底部按钮可见,你需要调整按钮的位置,使它们不重叠(因为它们的偏移值都会导致轻微的重叠)-我在这里将顶部设置为30%:http://jsfiddle.net/twvn1z3s/2/

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