我试图使用下面的Pyton脚本给多个收件人发电子邮件。
这是我的脚本,我想我的问题是在‘sendmail’部分,但不知道如何修复它:
gmail_user = "sender@email.com"
gmail_pwd = "sender_password"
recipients = ['recipient1@email.com','recipient2@email.com']
def mail(to, subject, text, attach):
msg = MIMEMultipart()
msg['From'] = gmail_user
msg['To'] = ", ".join(recipients)
msg['Subject'] = subject
msg.attach(MIMEText(text))
part = MIMEBase('application', 'octet-stream')
part.set_payload(open(attach, 'rb').read())
Encoders.encode_base64(part)
part.add_header('Content-Disposition',
'attachment; filename="%s"' % os.path.basename(attach))
msg.attach(part)
mailServer = smtplib.SMTP("smtp.gmail.com", 587)
mailServer.ehlo()
mailServer.starttls()
mailServer.ehlo()
mailServer.login(gmail_user, gmail_pwd)
mailServer.sendmail(gmail_user, to, msg.as_string())
mailServer.close()
mail("recipient1@email.com, recipient2@email.com",
"Subject",
"Message",
"attchachment")
任何见解都将不胜感激。
最好,
马特
发布于 2018-07-23 10:30:35
这段代码可以满足你想做的事。如果你发现了bug,请告诉我(我已经测试过它了,它可以运行):
import email as em
import smtplib as smtp
import os
ENDPOINTS = {KEY: 'value@domain.com'}
class BoxWriter(object):
def __init__(self):
pass
def dispatch(self, files, box_target, additional_targets=None, email_subject=None, body='New figures'):
"""
Send an email to multiple recipients
:param files: list of files to send--requires full path
:param box_target: Relevant entry ENDPOINTS dict
:param additional_targets: other addresses to send the same email
:param email_subject: optional title for email
"""
destination = ENDPOINTS.get(box_target, None)
if destination is None:
raise Exception('Target folder on Box does not exist')
recipients = [destination]
if additional_targets is not None:
recipients.extend(additional_targets)
subject = 'Updating files'
if email_subject is not None:
subject = email_subject
message = em.MIMEMultipart.MIMEMultipart()
message['From'] = 'user@domain.com'
message['To'] = ', '.join(recipients)
message['Date'] = em.Utils.formatdate(localtime=True)
message['Subject'] = subject
message.attach(em.MIMEText.MIMEText(body + '\n' +'Contents: \n{0}'.format('\n'.join(files))))
for f in files:
base = em.MIMEBase.MIMEBase('application', "octet-stream")
base.set_payload(open(f, 'rb').read())
em.Encoders.encode_base64(base)
base.add_header('Content-Disposition', 'attachment; filename={0}'.format(os.path.basename(f)))
message.attach(base)
conn = smtp.SMTP('smtp.gmail.com', 587)
un = 'user@gmail.com'
pw = 'test1234'
conn.starttls()
conn.login(un, pw)
conn.sendmail('user@domain.com', recipients, message.as_string())
conn.close()
发布于 2018-07-23 11:11:00
应该更像是
mail(["recipient1@email.com", "recipient2@email.com"],
"Subject",
"Message",
"attchachment")
你已经声明了一个接收者数组,在全局范围内,你可以使用它而不将它作为参数传递给mail
。
https://stackoverflow.com/questions/-100005617
复制相似问题