blocks|key|4119401|text|如果结果需要是一个数组数组，每个字符串的每个字符都包含一个元素，则可以在循环或映射中使用空字符串拆分每个字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4119402|let+res+=+[];
let+strArr+=+["10100",+"10111",+"11111",+"01010"];
strArr.map((str)+=>+{
++++res.push(str.split(''))
});
console.log(res);|code-block|syntax|javascript|4119403|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>If the result needs to be an array of array containing one element per character of a string, you can split each string with an empty string in a loop or map.</p>

<pre><code>let res = [];
let strArr = ["10100", "10111", "11111", "01010"];
strArr.map((str) =&gt; {
    res.push(str.split(''))
});
console.log(res);
</code></pre>


blocks|key|4119428|text|循环遍历每个项目，并将其内容扩展到一个数组中-然后转换为一个数字。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4119429|let+newArr+=+strArr.map(item+=>+[...item].map(Number));|offset|length|style|CODE|4119430|entityMap^0|0|0|1J|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

<p>Loop over each item and spread its content into an array - then convert to a number.</p>

<p><code>let newArr = strArr.map(item =&gt; [...item].map(Number));</code></p>


blocks|key|4119714|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4119715|let+inArr+=+["10100",+"10111",+"11111",+"01010"];
let+outArr+=+inArr.map(+line+=>+line.split("").map(++item+=>++%2Bitem++)+);

console.log(outArr);|code-block|syntax|javascript|4119716|4119717|let+inArr+=+["10100",+"10111",+"11111",+"01010"];
let+outArr+=+inArr.map(+line+=>+line.split("").map(++item+=>++%2Bitem++)+);|4119718|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|M|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|H|3|I|5|D|7|O|8|@]|9|@]|A|$E|F]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let inArr = ["10100", "10111", "11111", "01010"];
let outArr = inArr.map( line =&gt; line.split("").map(  item =&gt;  +item  ) );

console.log(outArr);</code></pre>
</div>
</div>
</p>

<pre><code>let inArr = ["10100", "10111", "11111", "01010"];
let outArr = inArr.map( line =&gt; line.split("").map(  item =&gt;  +item  ) );
</code></pre>


blocks|key|4119477|text|这样，您将拥有由0和1组成的2维数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4119478|const+newArr+=+strArr.map((a)+=>+a.split("").map(char+=>+char+===+"0"?+0:+1))|code-block|syntax|javascript|4119479|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>this way, you will have 2d array of zero and ones    </p>

<pre><code>const newArr = strArr.map((a) =&gt; a.split("").map(char =&gt; char === "0"? 0: 1))
</code></pre>


blocks|key|4119509|text|您可以从字符串和映射编号中获取迭代值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4119510|​|4119511|var+array+=+["10100",+"10111",+"11111",+"01010"],
++++matrix+=+array.map(s+=>+Array.from(s,+Number));
++++
console.log(matrix);|code-block|syntax|javascript|4119512|.as-console-wrapper+{+max-height:+100%25+!important;+top:+0;+}|4119513|4119514|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|K|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

<p>You could get the iterables from string and map numbers.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var array = ["10100", "10111", "11111", "01010"],
    matrix = array.map(s =&gt; Array.from(s, Number));
    
console.log(matrix);</code></pre>
<pre class="snippet-code-css lang-css prettyprint-override"><code>.as-console-wrapper { max-height: 100% !important; top: 0; }</code></pre>
</div>
</div>
</p>


blocks|key|4119800|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4119801|let+strArr+=+["10100",+"10111",+"11111",+"01010"];
let+numColumns+=+strArr[0].length;
let+numRows+=+strArr.length;
let+string+=+strArr.join('');
let+result+=+[];

for+(let+row+=+0;+row+<+numRows;+row%2B%2B)+{
++result.push([]);
++for+(let+column+=+0;+column+<+numColumns;+column%2B%2B)+{
++++result[row].push(parseInt(string.charAt(row*5+%2B+column),+10));
++}
}

console.log(result);|code-block|syntax|javascript|4119802|4119803|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let strArr = ["10100", "10111", "11111", "01010"];
let numColumns = strArr[0].length;
let numRows = strArr.length;
let string = strArr.join('');
let result = [];

for (let row = 0; row &lt; numRows; row++) {
  result.push([]);
  for (let column = 0; column &lt; numColumns; column++) {
    result[row].push(parseInt(string.charAt(row*5 + column), 10));
  }
}

console.log(result);</code></pre>
</div>
</div>
</p>


<p>How do I convert this array : </p>

<pre><code>let strArr = ["10100", "10111", "11111", "01010"];
</code></pre>

<p>into a 2-d array.</p>

<p>The 2-d array will be :-</p>

<pre><code> 1 0 1 0 0
 1 0 1 1 1
 1 1 1 1 1
 0 1 0 1 0 
</code></pre>


How to convert an array of strings to a 2-dimensional array?

如何转换此数组：let strArr = ["10100", "10111", "11111", "01010"];转换成2-d数组。2-d数组将是:- 1 0 1 0 0 1 0 1 1 1 1 1 1 1 1 0 1 0 1 0 

问如何将字符串数组转换为二维数组？
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