blocks|key|4353766|text|我意识到有一种方法可以解决这个问题，所以我想如果python的初学者在未来使用python时遇到同样的疑问，我会把这篇文章贴出来：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4353767|metadata+=+client.files_list_folder('')
flist+=+[]
if+metadata.has_more+==+True:
++++m1+=+metadata.entries
++++cur+=+metadata.cursor
++++for+i+in+m1:
++++++++if+isinstance(i,+dropbox.files.FileMetadata):
++++++++++++flist.append([i.name,+i.size])
++++m2+=+client.files_list_folder_continue(cur)
++++while+m2.has_more+==+True:
++++++++for+i+in+m2.entries:
++++++++++++if+isinstance(i,+dropbox.files.FileMetadata):
++++++++++++++++flist.append([i.name,+i.size])
++++++++cur+=+m2.cursor
++++++++m2+=+client.files_list_folder_continue(cur)|code-block|syntax|javascript|4353768|获取dropbox文件夹的主目录中所有文件的名称和大小。|4353769|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I realized there was a way to solve this, so I figured I post this if a beginner at python stumbles into the same doubt using python in the future:

<pre><code>metadata = client.files_list_folder('')
flist = []
if metadata.has_more == True:
 m1 = metadata.entries
 cur = metadata.cursor
 for i in m1:
 if isinstance(i, dropbox.files.FileMetadata):
 flist.append([i.name, i.size])
 m2 = client.files_list_folder_continue(cur)
 while m2.has_more == True:
 for i in m2.entries:
 if isinstance(i, dropbox.files.FileMetadata):
 flist.append([i.name, i.size])
 cur = m2.cursor
 m2 = client.files_list_folder_continue(cur)
</code></pre>

That gets the name and size of all files in the home directory of the dropbox folder.

blocks|key|4353841|text|我相信使用这段代码，你会错过最后一次迭代:假设你有11189个条目。在我的例子中，files_list_folder每次返回2000。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4353842|metadata+=+client.files_list_folder('')
flist+=+[]
if+metadata.has_more+==+True:
++++m1+=+metadata.entries
++++cur+=+metadata.cursor
++++for+i+in+m1:
++++++++if+isinstance(i,+dropbox.files.FileMetadata):
++++++++++++flist.append([i.name,+i.size])
++++#+flist+now+has+2000+items
++++m2+=+client.files_list_folder_continue(cur)
++++while+m2.has_more+==+True:
++++++++for+i+in+m2.entries:
++++++++++++if+isinstance(i,+dropbox.files.FileMetadata):
++++++++++++++++flist.append([i.name,+i.size])
++++++++cur+=+m2.cursor
++++++++#+1st+time+:+flist+will+have+4000+and+m2.has_more==True
++++++++#+2nd+time+:+flist+will+have+6000+and+m2.has_more==True
++++++++#+3rd+time+:+flist+will+have+8000+and+m2.has_more==True
++++++++#+4th+time+:+flist+will+have+10000+and+m2.has_more==True
++++++++m2+=+client.files_list_folder_continue(cur)
++++++++#+5th+time+:+m2.entries+will+have+1189+files+but+m2.has_more==False
++++++++#+so+you'll+step+out+of+the+loop+without+iterating+through+those+1189+entries|code-block|syntax|javascript|4353843|在while循环之外，您需要最后一次遍历m2.entry。|4353844|我知道这是一个一年前的问题，但我自己也遇到了这个错误。|4353845|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I believe that with this code you'll miss on the last iteration:
Let's say you have 11189 items. In my case files_list_folder return 2000 each time.

<pre><code>metadata = client.files_list_folder('')
flist = []
if metadata.has_more == True:
 m1 = metadata.entries
 cur = metadata.cursor
 for i in m1:
 if isinstance(i, dropbox.files.FileMetadata):
 flist.append([i.name, i.size])
 # flist now has 2000 items
 m2 = client.files_list_folder_continue(cur)
 while m2.has_more == True:
 for i in m2.entries:
 if isinstance(i, dropbox.files.FileMetadata):
 flist.append([i.name, i.size])
 cur = m2.cursor
 # 1st time : flist will have 4000 and m2.has_more==True
 # 2nd time : flist will have 6000 and m2.has_more==True
 # 3rd time : flist will have 8000 and m2.has_more==True
 # 4th time : flist will have 10000 and m2.has_more==True
 m2 = client.files_list_folder_continue(cur)
 # 5th time : m2.entries will have 1189 files but m2.has_more==False
 # so you'll step out of the loop without iterating through those 1189 entries
</code></pre>

You'll need to iterate one last time through m2.entries once outside the while loop.

I know this is a year old question but I just came across this error myself.

blocks|key|4353943|text|这两个答案都是准确的，但为了完成戴维德的代码，我会在while中添加一条else语句来获取剩余的文件：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4353944|flist+=+[]
if+metadata.has_more+==+True:
++++m1+=+metadata.entries
++++cur+=+metadata.cursor
++++for+i+in+m1:
++++++++if+isinstance(i,+dropbox.files.FileMetadata):
++++++++++++flist.append([i.name,+i.size])
++++#+flist+now+has+2000+items
++++m2+=+client.files_list_folder_continue(cur)
++++while+m2.has_more+==+True:
++++++++for+i+in+m2.entries:
++++++++++++if+isinstance(i,+dropbox.files.FileMetadata):
++++++++++++++++flist.append([i.name,+i.size])
++++++++cur+=+m2.cursor
++++++++m2+=+client.files_list_folder_continue(cur)entries
++++else:
++++++++m_final+=+client.files_list_folder_continue(cur)
++++++++for+i+in+m_final.entries:
++++++++++++if+isinstance(i,+dropbox.files.FileMetadata):
++++++++++++flist.append([i.name,+i.size])|code-block|syntax|javascript|4353945|这样，您就可以在不中断循环的情况下检索所有文件。|4353946|entityMap^0|Q|5|10|4|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

Both answers are accurate, but only to complete Daviid's code, I'd add an <code>else</code> statement in the <code>while</code> to get the remaining files: 

<pre><code>flist = []
if metadata.has_more == True:
 m1 = metadata.entries
 cur = metadata.cursor
 for i in m1:
 if isinstance(i, dropbox.files.FileMetadata):
 flist.append([i.name, i.size])
 # flist now has 2000 items
 m2 = client.files_list_folder_continue(cur)
 while m2.has_more == True:
 for i in m2.entries:
 if isinstance(i, dropbox.files.FileMetadata):
 flist.append([i.name, i.size])
 cur = m2.cursor
 m2 = client.files_list_folder_continue(cur)entries
 else:
 m_final = client.files_list_folder_continue(cur)
 for i in m_final.entries:
 if isinstance(i, dropbox.files.FileMetadata):
 flist.append([i.name, i.size])
</code></pre>

That way you can retrieve all the files without breaking the loop.

The Dropbox account I'm connected to using the Dropbox Python API has about 10k files in it's main folder. I'm interested in getting the metadata information of all files, the thing is that when I call the following:

<pre><code>client = dropbox.Dropbox('TOKEN HERE')
metadata = client.files_list_folder('').entries
fname = []
for i in metadata:
 fname.append(i)
print(len(fname))
</code></pre>

It prints out only 2000 files. I find it suspicious that it only prints the info of such round number, which makes me assume that's a hard limit. 

I know there's the <code>files_list_folder_continue</code> function which, if I understood correctly, continues to look for metadata where the <code>files_list_folder</code> function left off but Im not sure how to implement it. I tried the following:

<pre><code>metadata = client.files_list_folder('').entries
metadata1 = client.files_list_folder_continue('').entries
met = pd.concat([metadata, metadata1], axis=0)
</code></pre>

But it produces the following error: <code>dropbox.stone_validators.ValidationError: '' must be at least 1 characters, got 0</code>. Clearly it has to do with the fact that I dont know how to use the <code>files_list_folder_continue</code> function. How can these be used?

Getting metadata of all files using Dropbox Python API

Python

我使用Dropbox Python API连接到的Dropbox帐户在其主文件夹中有大约10k个文件。我对获取所有文件的元数据信息很感兴趣，问题是当我调用以下代码时：client = dropbox.Dropbox('TOKEN HERE')metadata = client.files_list_folder('')...

问使用Dropbox Python API获取所有文件的元数据
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