blocks|key|4444018|text|您可以使用componentsSeparatedByString()方法来获取字符串数组。使用"+"作为分隔符。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4444019|因为您知道如何获取字符串的第一个字符，所以现在只需对数组中的每个字符串执行此操作。|4444020|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.apple.com/library/ios/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/index.html#//apple_ref/occ/instm/NSString/componentsSeparatedByString:^0|5|T|1B|3|5|T|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]|$9|S|A|T|B|C]]|D|@$9|U|A|V|1|W]]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

You can use the <a href="https://developer.apple.com/library/ios/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/index.html#//apple_ref/occ/instm/NSString/componentsSeparatedByString:" rel="nofollow"><code>componentsSeparatedByString()</code></a> method to get an array of strings. Use <code>" "</code> as the separator. 

Since you know how to get the first char of a string, now you just do that for each string in the array.

blocks|key|4444088|text|你可以试试这段代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4444089|4444090|let+stringInput+=+"First+Last"
let+stringInputArr+=+stringInput.components(separatedBy:"+")
var+stringNeed+=+""

for+string+in+stringInputArr+{
++++stringNeed+%2B=+String(string.first!)
}

print(stringNeed)|code-block|syntax|javascript|4444091|4444092|如果componentsSeparatedByString有问题，您可以尝试按字符空间分隔，然后在数组中继续，您可以删除所有空字符串。|offset|length|style|CODE|4444093|希望这对你有所帮助！|4444094|entityMap^0|0|0|0|0|2|R|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|T|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|U|8|@]|9|@]|A|$F|G]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|W|8|@$K|X|L|Y|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|Z|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|R|$]]

You can try this code:
<hr />
<pre><code>let stringInput = &quot;First Last&quot;
let stringInputArr = stringInput.components(separatedBy:&quot; &quot;)
var stringNeed = &quot;&quot;

for string in stringInputArr {
 stringNeed += String(string.first!)
}

print(stringNeed)
</code></pre>
<hr />
If have problem with <code>componentsSeparatedByString</code> you can try seperate by character space and continue in array you remove all string empty.
Hope this help!

blocks|key|4443813|text|或使用.reduce()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4443814|4443815|let+str+=+"Stack+Over+Flow"
let+desiredOutPut+=+str
++++.components(separatedBy:+"+")
++++.reduce("")+{+$0+%2B+($1.first.map(String.init)+??+"")+}|code-block|syntax|javascript|4443816|4443817|print(desiredOutPut)|4443818|entityMap^0|3|9|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]|$1|G|3|H|5|I|7|U|8|@]|D|@]|E|$J|K]]|$1|L|3|-4|5|6|7|V|8|@]|D|@]|E|$]]|$1|M|3|N|5|I|7|W|8|@]|D|@]|E|$J|K]]|$1|O|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|P|$]]

Or by using <code>.reduce()</code>:
<hr />
<pre><code>let str = &quot;Stack Over Flow&quot;
let desiredOutPut = str
 .components(separatedBy: &quot; &quot;)
 .reduce(&quot;&quot;) { $0 + ($1.first.map(String.init) ?? &quot;&quot;) }
</code></pre>
<hr />
<pre><code>print(desiredOutPut)
</code></pre>

blocks|key|4443864|text|var+String1+=+"Stack+Over+Flow"
let+arr+=+String1.componentsSeparatedByString("+")
var+desiredoutput+=+""
for+str+in+arr+{
++++if+let+char+=+str.characters.first+{
++++++++desiredoutput+%2B=+String(char)
++++}
}
desiredoutput|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4443865|顺便说一下，我认为变量名的约定是驼峰式的，第一个字符是小写字母，比如"string1“，而不是"String1”。|unstyled|4443866|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>var String1 = "Stack Over Flow"
let arr = String1.componentsSeparatedByString(" ")
var desiredoutput = ""
for str in arr {
 if let char = str.characters.first {
 desiredoutput += String(char)
 }
}
desiredoutput
</code></pre>

By the way, the convention for variable names I believe is camel-case with a lowercase letter for the first character, such as "string1" as opposed to "String1"

blocks|key|4443902|text|为了让它更优雅，我会用下面的代码为swift+3.0+String类做一个扩展。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4443903|extension+String
{
++++public+func+getAcronyms(separator:+String+=+"")+->+String
++++{
++++++++let+acronyms+=+self.components(separatedBy:+"+").map({+String($0.characters.first!)+}).joined(separator:+separator);
++++++++return+acronyms;
++++}
}|code-block|syntax|javascript|4443904|之后你可以像这样使用它：|4443905|++let+acronyms+=+"Hello+world".getAcronyms();
++//will+print:+Hw

++let+acronymsWithSeparator+=+"Hello+world".getAcronyms(separator:+".");
++//will+print:+H.w

++let+upperAcronymsWithSeparator+=+"Hello+world".getAcronyms(separator:+".").uppercased();
++//will+print:+H.W|4443906|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

To keep it more elegant I would make an extension for the swift 3.0 String class with the following code.

<pre><code>extension String
{
 public func getAcronyms(separator: String = "") -&gt; String
 {
 let acronyms = self.components(separatedBy: " ").map({ String($0.characters.first!) }).joined(separator: separator);
 return acronyms;
 }
}
</code></pre>

Afterwords you can just use it like this:

<pre><code> let acronyms = "Hello world".getAcronyms();
 //will print: Hw

 let acronymsWithSeparator = "Hello world".getAcronyms(separator: ".");
 //will print: H.w

 let upperAcronymsWithSeparator = "Hello world".getAcronyms(separator: ".").uppercased();
 //will print: H.W
</code></pre>

blocks|key|4443911|text|以下是swift3中的更改|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4443912|++++++let+stringInput+=+"Stack+Overflow"
++++++let+stringInputArr+=+stringInput.components(separatedBy:+"+")
++++++var+stringNeed+=+""

++++++for+string+in+stringInputArr+{
+++++++++++stringNeed+=+stringNeed+%2B+String(string.characters.first!)
++++++}

++++++print(stringNeed)|code-block|syntax|javascript|4443913|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is the changes in swift3

<pre><code> let stringInput = "Stack Overflow"
 let stringInputArr = stringInput.components(separatedBy: " ")
 var stringNeed = ""

 for string in stringInputArr {
 stringNeed = stringNeed + String(string.characters.first!)
 }

 print(stringNeed)
</code></pre>

blocks|key|4443926|text|为了完整起见，这是一个具有非常强大的enumerateSubstrings(in:options:_:的解决方案|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4443927|let+string+=+"Stack+Over+Flow"

var+result+=+""
string.enumerateSubstrings(in:+string.startIndex..<string.endIndex,+options:+.byWords)+{+(substring,+_,+_,+_)+in
++++if+let+substring+=+substring+{+result+%2B=+substring.prefix(1)+}
}
print(result)|code-block|syntax|javascript|4443928|entityMap^0|I|X|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

For the sake of completeness this is a solution with very powerful <code>enumerateSubstrings(in:options:_:</code>

<pre><code>let string = "Stack Over Flow"

var result = ""
string.enumerateSubstrings(in: string.startIndex..&lt;string.endIndex, options: .byWords) { (substring, _, _, _) in
 if let substring = substring { result += substring.prefix(1) }
}
print(result)
</code></pre>

blocks|key|4443932|text|let+inputString+=+"ABC+PQR+XYZ"
var+stringNeed+=+""

class+something
{
++++++++let+splits+=+inputString.components(separatedBy:+"+")
++++++++for+string+in+splits
++++++++{
++++++++++++stringNeed+=+stringNeed+%2B+String(string.first!)++++++
++++++++}
++++++++print(stringNeed)
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4443933|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>let inputString = "ABC PQR XYZ"
var stringNeed = ""

class something
{
 let splits = inputString.components(separatedBy: " ")
 for string in splits
 {
 stringNeed = stringNeed + String(string.first!) 
 }
 print(stringNeed)
}
</code></pre>

I want this:

<pre><code>var String1 = "Stack Over Flow"
var desiredOutPut = "SOF" // the first Character of each word in a single String (after space)
</code></pre>

I know how to get the first character from a string but have no idea what to do this with this problem.

How to get the first character of each word in a string?

我想要的是：var String1 = "Stack Over Flow"var desiredOutPut = "SOF" // the first Character of each word in a single String (after space)我知道如何从字符串中获取第一个字符，但不知道如何处理此问题...

问如何获取字符串中每个单词的第一个字符？
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问如何获取字符串中每个单词的第一个字符？
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