朋友们,我向java web服务方法发送了带有三个参数的JSON字符串。但是在java端,方法不能在控制台中打印。请告诉我我必须从下面的代码中修改什么?
String json = "";
HttpParams httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParams, 10000);
HttpConnectionParams.setSoTimeout(httpParams, 10000);
HttpClient httpclient = new DefaultHttpClient();
// Prepare a request object
HttpPost httpPost = new HttpPost(url);
HttpGet httpGet = new HttpGet(url);
JSONObject jsonObject = new JSONObject();
try {
jsonObject.put("name", "ghanshyam");
jsonObject.put("country", "India");
jsonObject.put("twitter", "ghahhd");
json = jsonObject.toString();
StringEntity se = new StringEntity(json);
se.setContentEncoding("UTF-8");
se.setContentType("application/json");
// 6. set httpPost Entity
System.out.println(json);
httpPost.setEntity(se);
httpGet.se
// 7. Set some headers to inform server about the type of the content
//httpPost.addHeader( "SOAPAction", "application/json" );
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
//String s = doGet(url).toString();
Toast.makeText(getApplicationContext(), "Data Sent", Toast.LENGTH_SHORT).show();
发布于 2014-04-08 20:09:46
使用以下代码将json发布到Java web-service:并获取字符串形式的resopnse。
JSONObject json = new JSONObject();
json.put("name", "ghanshyam");
json.put("country", "India");
json.put("twitter", "ghahhd");
HttpPost post = new HttpPost(url);
post.setHeader("Content-type", "application/json");
post.setEntity(new StringEntity(json.toString(), "UTF-8"));
DefaultHttpClient client = new DefaultHttpClient();
HttpResponse httpresponse = client.execute(post);
HttpEntity entity = httpresponse.getEntity();
InputStream stream = entity.getContent();
String result = convertStreamToString(stream);
您的convertStremToString()方法如下所示:
public static String convertStreamToString(InputStream is)
{
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try
{
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
}
catch (IOException e)
{
e.printStackTrace();
}
finally
{
try
{
is.close();
}
catch (IOException e)
{
e.printStackTrace();
}
}
return sb.toString();
}
https://stackoverflow.com/questions/22936367
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