用孵化的Java10 HttpClient重建HTTP流
用孵化的Java10 HttpClient重建HTTP流
提问于 2018-06-08 23:55:09
我正在尝试通过一个Java应用程序重建到HttpClient服务器的会话设置。我选择了incubated HttpClient provided with Java 9 and Java 10。
使用Chrome时，我从一个请求中捕获了这个头文件：
General
Request URL: https://<some_url>?user_id=1176&onlyDirectUserItems=true&onlyAssignedToUser=true&show=Unresolved&itemsFilter=0
Request Method: GET
Status Code: 302 Found
Remote Address: <theProxy>:8000
Referrer Policy: no-referrer-when-downgrade
Response Headers
Connection: Keep-Alive
Content-Length: 164
Content-Type: text/html; charset=iso-8859-1
Date: Fri, 08 Jun 2018 14:33:16 GMT
Keep-Alive: timeout=300, max=100
Location: https://<another_url>:443/nesp/app/plogin?agAppNa=app_me_company_ext&c=secure/name/password/uri&target=%22https://<another-usr>/browseIssues.spr?user_id=1176&onlyDirectUserItems=true&onlyAssignedToUser=true&show=Unresolved&itemsFilter=0%22
P3p: CP="NOI"
Server: Apache
Set-Cookie: IPCZQX03224bfb75=030003000000000000000000000000008f7aed69; path=/; domain=.me.de
Via: 1.1 <host> (Access Gateway-ag-7169149846802036-13837511)
Request Headers
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8
Accept-Encoding: gzip, deflate, br
Accept-Language: de-DE,de;q=0.9,en-US;q=0.8,en;q=0.7
Connection: keep-alive
Cookie: org.ditchnet.jsp.tabs.wiki=wiki-wysiwyg; ZNPCQ003-31393000=6c2f99a3; ZNPCQ003-32323200=cd188fdd
DNT: 1
Host: <host>
Upgrade-Insecure-Requests: 1
User-Agent: Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/66.0.3359.181 Safari/537.36
Query String Parameters
user_id: 1176
onlyDirectUserItems: true
onlyAssignedToUser: true
show: Unresolved
itemsFilter: 0可以看到的是，响应头提供了一个URL ( Header -key："location")，接下来我需要获取并调用它。但是对于我的http客户端，我失败了，状态码为400，几乎什么也得不到。
这是我的代码
url = "https://<some_url>?user_id=1176&onlyDirectUserItems=true&onlyAssignedToUser=true&show=Unresolved&itemsFilter=0";
HttpClient client = HttpClient.newBuilder()
.proxy(ProxySelector.of(new InetSocketAddress("<theProxy>", 8000)))
.cookieHandler(new CookieManager(null, CookiePolicy.ACCEPT_ALL))
.followRedirects(HttpClient.Redirect.SAME_PROTOCOL)
.build();
HttpRequest request = HttpRequest.newBuilder()
.header("User-Agent", "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:60.0) Gecko/20100101 Firefox/60.0")
.header("Upgrade-Insecure-Requests", "1")
// .header("Host", "<host>")
.header("Connection", "keep-alive")
.header("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8")
.header("Accept-Language", "de-DE,de;q=0.9,en-US;q=0.8,en;q=0.7")
.header("Accept-Encoding", "gzip, deflate, br")
.uri(new URI(url))
.build();
HttpResponse<String> response = client.send(request, HttpResponse.BodyHandler.asString());
HttpHeaders headers = response.headers();
Map<String, List<String>> headerMap= headers.map();
for (String key : headerMap.keySet()) {
System.out.println(">"+key+"<");
for (String value : headerMap.get(key)) {
System.out.println(" " + value);
}
}
System.out.println(response.statusCode());
System.out.println(response.body());我不知道可能出了什么问题，也不知道如何继续完成这项工作。我希望有人能告诉我下一步要做什么。
我也不明白的是:我必须删除头文件"Host“--因为我得到的响应是：”您的浏览器发送了一个此服务器无法理解的请求。“
与Chrome-listing中的标题完全相同
回答 1
Stack Overflow用户
发布于 2018-06-11 01:09:51
我可以用Apache HttpClient来运行它。我不知道孵化的HttpClient出了什么问题--但肯定有一个原因，那就是它不是Java9/10交付中完全集成的部分
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50764345
复制相关文章
相似问题