在下面的示例中,我需要从Sql Server SELECT语句中的完整路径解析HTML文件名:
Declare @x table(Id int primary key, form_url varchar(256))
Insert @x values (1, 'Agents/Accounting/Agent.html')
Insert @x values (2,
'Modules/Vendors/Vendors/VendorInformation/Vendor.html')
Insert @x values (3,
'Modules/Customers/Customers/AccountInformation/Account.html?AccountNo')
Select * from @x
注意:路径之间的级别数目是可变的,并且HTML文件名后面可能有数据。
我正在寻找的输出是:
发布于 2018-07-04 04:01:21
T-SQL不是为字符串操作而设计的。但也有可能实现你所需要的:
Select x.*, IIF(CHARINDEX('?', sub.s) > 0,
LEFT(sub.s, CHARINDEX('?', sub.s)-1),
sub.s) result
from @x x
CROSS APPLY (SELECT IIF(CHARINDEX('/',form_url) > 0,
RIGHT(form_url,CHARINDEX('/', REVERSE(form_url))-1),
form_url)) sub(s);
发布于 2018-07-04 03:56:08
您可以使用reverse
和charindex
来获取所有内容,直到最后一个斜杠,然后使用charindex
或substring
来限制HTML页面。
Declare @x table(Id int primary key, form_url varchar(256))
Insert @x values (1, 'Agents/Accounting/Agent.html')
Insert @x values (2,
'Modules/Vendors/Vendors/VendorInformation/Vendor.html')
Insert @x values (3,
'Modules/Customers/Customers/AccountInformation/Account.html?AccountNo')
Select
*
,FullPath = right(form_url,charindex('/',reverse(form_url)) - 1)
,OnlyHtml = left(right(form_url,charindex('/',reverse(form_url)) - 1) ,charindex('.html',right(form_url,charindex('/',reverse(form_url)) + 3)))
,AnotherOnlyHtml = right(substring(form_url,1,charindex('.html',form_url) + 4),charindex('/',reverse(substring(form_url,1,charindex('.html',form_url) + 4))) - 1)
from @x
发布于 2018-07-04 04:33:07
如果对帮助器函数感兴趣。这是一个修改过的解析/拆分函数,它接受两个非like分隔符。在您的例子中是"/"
和"?"
。您可能已经注意到附加了一个"?“以防你遗漏了一个。
示例
Select *
From @x
Cross Apply [dbo].[tvf-Str-Extract](form_url+'?','/','?') B
Reuturns
如果感兴趣的话函数
CREATE FUNCTION [dbo].[tvf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100))
Returns Table
As
Return (
with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(N) As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ),
cte3(N) As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1),
cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S)
Select RetSeq = Row_Number() over (Order By N)
,RetPos = N
,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1)
From (
Select *,RetVal = Substring(@String, N, L)
From cte4
) A
Where charindex(@Delimiter2,RetVal)>1
)
/*
Max Length of String 1MM characters
Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...'
Select * From [dbo].[tvf-Str-Extract] (@String,'[[',']]')
*/
https://stackoverflow.com/questions/51161905
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