如何让一个函数在swift中每秒执行一次？
如何让一个函数在swift中每秒执行一次？
提问于 2015-05-07 09:16:34
我想在我正在工作的游戏中在我的场景的顶部添加一个分数。分数将基于你持续的时间，并且每秒都会增加。提前感谢您的帮助！
import SpriteKit
class easyScene: SKScene {
let scrollBarEasyBottom = SKSpriteNode(imageNamed: "scrollBarEasyBottom")
let scrollBarEasyTop = SKSpriteNode(imageNamed: "scrollBarEasyTop")
let ball = SKSpriteNode(imageNamed: "ball")
var origSBEBpositionX = CGFloat(0)
var origSBETpositionX = CGFloat(0)
var maxSBEBX = CGFloat(0)
var SBEBSpeed = 5
var maxSBETX = CGFloat(0)
var SBETSpeed = 5
var score = 0
var timer: NSTimer?
var scoreText = SKLabelNode(fontNamed: "Kailasa")
override func didMoveToView(view: SKView) {
println("Easy Scene is the location")
self.backgroundColor = UIColor.blackColor()
self.scrollBarEasyBottom.position = CGPoint(x:0, y:270)
self.addChild(self.scrollBarEasyBottom)
self.scrollBarEasyBottom.yScale = 0.2
self.origSBEBpositionX = self.scrollBarEasyBottom.position.x
// end scrollBarEasyBottom
self.scrollBarEasyTop.position = CGPoint(x:20, y:400)
self.addChild(self.scrollBarEasyTop)
self.scrollBarEasyTop.yScale = 0.2
self.origSBETpositionX = self.scrollBarEasyTop.position.x
// end scrollBarEasyTop
self.ball.position = CGPoint(x:40, y:293)
self.addChild(self.ball)
self.ball.yScale = 0.17
self.ball.xScale = 0.17
// end ball
self.maxSBEBX = self.scrollBarEasyBottom.size.width - self.frame.size.width
self.maxSBEBX *= -1
self.maxSBETX = self.scrollBarEasyTop.size.width - self.frame.size.width
self.maxSBETX *= -1
//
self.scoreText.text = "0"
self.scoreText.fontSize = 60
self.scoreText.position = CGPoint(x: CGRectGetMidX(self.frame), y: 500)
self.scoreText.text = String(self.score)
self.addChild(self.scoreText)
timer = NSTimer.scheduledTimerWithTimeInterval(1, target: self, selector: Selector("scoreIncrease") , userInfo: nil, repeats: true)
func scoreIncrease (){
score++
println(score)
}
}
override func update(currentTime: NSTimeInterval) {
if self.scrollBarEasyBottom.position.x <= maxSBEBX + 1200 {
self.scrollBarEasyBottom.position.x = self.origSBEBpositionX
}
if self.scrollBarEasyTop.position.x <= maxSBETX + 1200 {
self.scrollBarEasyTop.position.x = self.origSBETpositionX
}
scrollBarEasyBottom.position.x -= CGFloat(self.SBEBSpeed)
scrollBarEasyTop.position.x -= CGFloat(self.SBETSpeed)
// moving bars
var degreeRotation = CDouble(self.SBEBSpeed) * M_PI / 180
self.ball.zRotation -= CGFloat(degreeRotation)
//rotate ball
}
}在运行这段代码之后，我总是得到一个
发送到实例错误的
无法识别的选择器
回答 7
Stack Overflow用户
发布于 2015-05-07 16:05:06
您可以像这样使用一个：
var timer = NSTimer()
override func viewDidLoad() {
scheduledTimerWithTimeInterval()
}
func scheduledTimerWithTimeInterval(){
// Scheduling timer to Call the function "updateCounting" with the interval of 1 seconds
timer = NSTimer.scheduledTimerWithTimeInterval(1, target: self, selector: Selector("updateCounting"), userInfo: nil, repeats: true)
}
func updateCounting(){
NSLog("counting..")
}Swift 3:
var timer = Timer()
override func viewDidLoad() { // Use for the app's interface
scheduledTimerWithTimeInterval()
}
override func didMove(to view: SKView) { // As part of a game
scheduledTimerWithTimeInterval()
}
func scheduledTimerWithTimeInterval(){
// Scheduling timer to Call the function "updateCounting" with the interval of 1 seconds
timer = Timer.scheduledTimer(timeInterval: 1, target: self, selector: #selector(self.updateCounting), userInfo: nil, repeats: true)
}
@objc func updateCounting(){
NSLog("counting..")
}Swift 5:
注意:此解决方案与iOS 10.0+兼容。
// If needing to check for iOS compatibility use
// if #available(iOS 10.0, *) {code}
var timer = Timer()
override func viewDidLoad() {
self.timer = Timer.scheduledTimer(withTimeInterval: 1, repeats: true, block: { _ in
updateCounting()
})
}
func updateCounting(){
print("counting...")
}然后，您可以使用以下命令使计时器无效(停止)：
timer.invalidate()Stack Overflow用户
发布于 2015-05-07 09:25:33
在swift中有一个叫做NSTimer的东西可以解决你的问题。我已经给出了一个例子，比如你可以如何使用它。只需根据您的目的进行自定义即可。
var timer = NSTimer.scheduledTimerWithTimeInterval(1.0,
target: self,
selector: Selector("yourMethodToCall"),
userInfo: nil,
repeats: true)将这一行添加到需要重复调用函数的位置。
-
1.0指的是1秒。将call yourMethodName repeats的selector更改为true以每秒调用该函数。
试试这个，如果你卡在什么地方了，请告诉我。谢谢。
Stack Overflow用户
发布于 2017-02-23 23:40:04
Swift 3
找到这个解决方案，它对我很有效
weak var timer: Timer?
var timerDispatchSourceTimer : DispatchSourceTimer?
func startTimer() {
if #available(iOS 10.0, *) {
timer = Timer.scheduledTimer(withTimeInterval: 3, repeats: true) { [weak self] _ in
// do something here
}
} else {
// Fallback on earlier versions
timerDispatchSourceTimer = DispatchSource.makeTimerSource(flags: [], queue: DispatchQueue.main)
timerDispatchSourceTimer?.scheduleRepeating(deadline: .now(), interval: .seconds(60))
timerDispatchSourceTimer?.setEventHandler{
// do something here
}
timerDispatchSourceTimer?.resume()
}
}
func stopTimer() {
timer?.invalidate()
//timerDispatchSourceTimer?.suspend() // if you want to suspend timer
timerDispatchSourceTimer?.cancel()
}
// if appropriate, make sure to stop your timer in `deinit`
deinit {
stopTimer()
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/30090309
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