问查找给定字符串的下一个更大排列的算法

EN

function nextPermutation(array) {
    var i = array.length - 1;
    while (i > 0 && array[i - 1] >= array[i]) {
        i--;
    }

    if (i <= 0) {
        return false;
    }

    var j = array.length - 1;

    while (array[j] <= array[i - 1]) {
        j--;
    }

    var temp = array[i - 1];
    array[i - 1] = array[j];
    array[j] = temp;

    j = array.length - 1;

    while (i < j) {
        temp = array[i];
        array[i] = array[j];
        array[j] = temp;
        i++;
        j--;
    }

    return array;
}

1. Iterate over every character, we will get the last value i (starting from the first character) that satisfies the given condition S[i] < S[i + 1]
2. Now, we will get the last value j such that S[i] < S[j]
3. We now interchange S[i] and S[j]. And for every character from i+1 till the end, we sort the characters. i.e., sort(S[i+1]..S[len(S) - 1])