如何创建一个在游戏中打印整个请求和响应的方法？
如何创建一个在游戏中打印整个请求和响应的方法？
提问于 2018-04-07 17:42:53
我想创建一个帮助器方法，它可以从Controller调用，并打印Request的不同参数。我试图像下面这样做，但我需要将类型参数传递给Request。我应该为类型参数传递什么？
import play.api.mvc.Request
package object utilities {
def printPlayHttpRequest (request:Request): Unit ={ //Request needs type parameter. What should I pass as type parameter?
}
}查看Request对象的apply方法，似乎传递的类型参数对应于主体类型。那么我需要传递一些体型吗？
def apply[A](rh: RequestHeader, body: A): Request[A] 回答 1
Stack Overflow用户
回答已采纳
发布于 2018-04-07 17:49:56
根据Play文档，我认为Request[A]中的A对应于body类型，它可以是请求body的任何Scala类型，例如String、NodeSeq、ArrayByte、JsonValue或java.io.File，只要我们有能够处理它的body解析器
来自文档
Previously we said that an Action was a Request => Result function. This is not entirely true. Let’s have a more precise look at the Action trait:
trait Action[A] extends (Request[A] => Result) {
def parser: BodyParser[A]
}
First we see that there is a generic type A, and then that an action must define a BodyParser[A]. With Request[A] being defined as:
trait Request[+A] extends RequestHeader {
def body: A
}
The A type is the type of the request body. We can use any Scala type as the request body, for example String, NodeSeq, Array[Byte], JsonValue, or java.io.File, as long as we have a body parser able to process it.
To summarize, an Action[A] uses a BodyParser[A] to retrieve a value of type A from the HTTP request, and to build a Request[A] object that is passed to the action code.下面是我的实现
import play.api.mvc.{AnyContent, Request}
package object utilities {
def printPlayHttpRequest (request:Request[AnyContent]): Unit ={
println(s"Attr: ${request.attrs}, \n Body: ${request.body}, \n connection: ${request.connection}, \n headers: ${request.headers}, \n method: ${request.method}, \n target: ${request.target}, \n version: ${request.version}, \n mediatype: ${request.mediaType}")
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/49705977
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