blocks|key|3139688|text|Java和JavaScript+Date.getTime()方法返回自1970年1月1日格林尼治标准时间00:00:00以来的毫秒数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3139689|由于.NET以刻度表示日期(1刻度=0.1纳秒或0.0001毫秒)，因此我们必须使用转换公式，其中621355968000000000是刻度基准日期之间的偏移量，10000是每毫秒刻度数。|3139690|Ticks+=+(MilliSeconds+*+10000)+%2B+621355968000000000
MilliSeconds+=+(Ticks+-+621355968000000000)+/+10000|code-block|syntax|javascript|3139691|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The Java and JavaScript Date.getTime() methods return the number of milliseconds since 1 Jan 1970 00:00:00 GMT.

Since .NET 
represents dates in Ticks (1 Tick = 0.1 nanoseconds or 0.0001 milliseconds) since 1 Jan 0001 00:00:00 GMT, we must use a 
conversion formula where 621355968000000000 is the offset between the base dates in Ticks and 10000 the number of Ticks per 
Millisecond.

<pre><code>Ticks = (MilliSeconds * 10000) + 621355968000000000
MilliSeconds = (Ticks - 621355968000000000) / 10000
</code></pre>

blocks|key|249610|text|(DateTime.Now+-+new+DateTime+(1970,+1,+1)).TotalMilliseconds|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|249611|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>(DateTime.Now - new DateTime (1970, 1, 1)).TotalMilliseconds
</code></pre>

blocks|key|248070|text|由于JavaScript时间相对于UTC是的，所以我认为你需要这样的东西：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|248071|var+st+=+new+DateTime(1970,+1,+1,+0,+0,+0,+DateTimeKind.Utc);
var+t++=+(DateTime.Now.ToUniversalTime()+-+st);
//+t.TotalMilliseconds|code-block|syntax|javascript|248072|现在可以使用Timespan的TotalMilliseconds属性了。|CODE|248073|entityMap^0|L|G|0|0|0|10|6|8|F|H|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|S|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|T|8|@$9|U|A|V|B|C]|$9|W|A|X|B|M]|$9|Y|A|Z|B|M]]|D|@]|E|$]]|$1|N|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|O|$]]

Since JavaScript time is with respect to UTC, I think you will need something like this:

<pre><code>var st = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);
var t = (DateTime.Now.ToUniversalTime() - st);
// t.TotalMilliseconds
</code></pre>

Now you can use the <code>TotalMilliseconds</code> property of the <code>Timespan</code>.

blocks|key|246118|text|我想这将会起到作用:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|246119|public+double+MilliTimeStamp(DateTime+TheDate)
++++++++{
++++++++++++DateTime+d1+=+new+DateTime(1970,+1,+1);
++++++++++++DateTime+d2+=+TheDate.ToUniversalTime();
++++++++++++TimeSpan+ts+=+new+TimeSpan(d2.Ticks+-+d1.Ticks);

++++++++++++return+ts.TotalMilliseconds;
++++++++}|code-block|syntax|javascript|246120|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I guess this will do the trick :)

<pre><code>public double MilliTimeStamp(DateTime TheDate)
 {
 DateTime d1 = new DateTime(1970, 1, 1);
 DateTime d2 = TheDate.ToUniversalTime();
 TimeSpan ts = new TimeSpan(d2.Ticks - d1.Ticks);

 return ts.TotalMilliseconds;
 }
</code></pre>

blocks|key|246122|text|您可以使用此解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|246123|private+int+GetTime()
{
+++var+time+=+(DateTime.Now.ToUniversalTime()+-+new+DateTime(1970,+1,+1));
+++return+(int)(time.TotalMilliseconds+%2B+0.5);
}|code-block|syntax|javascript|246124|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use this solution:
<pre><code>private int GetTime()
{
 var time = (DateTime.Now.ToUniversalTime() - new DateTime(1970, 1, 1));
 return (int)(time.TotalMilliseconds + 0.5);
}

 
</code></pre>

blocks|key|2925575|text|正确的实现(假设当前时间)如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2925576|DateTime+utcNow+=+DateTime.UtcNow;
DateTime+epoch+=+new+DateTime(1970,+1,+1,+0,+0,+0,+DateTimeKind.Utc);
long+ts+=+(long)((utcNow+-+epoch).TotalMilliseconds);|code-block|syntax|javascript|2925577|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The correct implementation (assuming the current time) is as follows:

<pre><code>DateTime utcNow = DateTime.UtcNow;
DateTime epoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);
long ts = (long)((utcNow - epoch).TotalMilliseconds);
</code></pre>

blocks|key|251049|text|这是一个基于Enigma+State's+answer的扩展方法|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|251050|public+static+Int64+GetJavascriptTimeStamp(this+DateTime+dt)
{
++++var+nineteenseventy+=+new+DateTime(1970,+1,+1);
++++var+timeElapsed+=+(dt.ToUniversalTime()+-+nineteenseventy);
++++return+(Int64)(timeElapsed.TotalMilliseconds+%2B+0.5);
}|code-block|syntax|javascript|251051|要在当前时间使用它：|251052|var+timeStamp+=+DateTime.Now.GetJavascriptTimeStamp();|style|CODE|251053|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/8134246/3103633^0|6|L|0|0|0|0|0|1I|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|11|8|@]|9|@]|C|$]]|$1|K|3|L|5|6|7|12|8|@$A|13|B|14|M|N]]|9|@]|C|$]]|$1|O|3|-4|5|6|7|15|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

Here is an extension method based off <a href="https://stackoverflow.com/a/8134246/3103633">Enigma State's answer</a>

<pre><code>public static Int64 GetJavascriptTimeStamp(this DateTime dt)
{
 var nineteenseventy = new DateTime(1970, 1, 1);
 var timeElapsed = (dt.ToUniversalTime() - nineteenseventy);
 return (Int64)(timeElapsed.TotalMilliseconds + 0.5);
}
</code></pre>

To use it for the current time:

<code>var timeStamp = DateTime.Now.GetJavascriptTimeStamp();</code>

blocks|key|3139906|text|当前接受的答案返回一个不正确的int。它必须是Int64或long。这只是将Matt+Johnson-Pint+(由Adaptabi编辑)提供的正确答案重写为一行。请接受Matt+Johnson-Pint的回答。我在控制台中对照实际的javascript+new+Date().getTime()进行了检查，以验证它是否返回相同的数字。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3139907|long+JavascriptGetTime()
{
++++return+(long)DateTime.UtcNow.Subtract(new+DateTime(1970,+1,+1,+0,+0,+0,+DateTimeKind.Utc)).TotalMilliseconds;++++++++++++
}|code-block|syntax|javascript|3139908|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The currently accepted answer returns an int which is incorrect. It has to be Int64 or long. This is just rewriting the correct answer provided by Matt Johnson-Pint (and edited by Adaptabi) as one line. Please accept Matt Johnson-Pint's answer. I checked it against actual javascript new Date().getTime() in the console to verify it returns the same number.

<pre class="lang-csharp prettyprint-override"><code>long JavascriptGetTime()
{
 return (long)DateTime.UtcNow.Subtract(new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc)).TotalMilliseconds; 
}
</code></pre>

What is the best way in c# to get the same result of javascript date.gettime() call?

<blockquote>
 The getTime() method returns the number of milliseconds since midnight of January 1, 1970 and the specified date.
</blockquote>

C# version of Javascript Date.getTime()

Java

在c#中，获得相同的javascript date.gettime()调用结果的最佳方式是什么？ getTime()方法返回从1970年1月1日午夜到指定日期的毫秒数。

问Javascript Date.getTime()的C#版本
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