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模拟java.net.ConnectException:连接超时
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Stack Overflow用户
提问于 2015-07-09 17:44:53
回答 1查看 2.6K关注 0票数 2

我想在我的java应用程序中人为地创建一个连接超时来测试我的连接超时处理。我已经看过这个线程Artificially create a connection timeout error了。

但是,当我尝试执行建议的操作时,比如http://10.255.255.1http://www.google.com:81,我用来进行http调用的库(Apache http client3.1)会给我一个连接被拒绝的异常,而不是超时。

[9/07/15 19:28:45:000 EST] 00000088 SystemErr     R IOException Connection refused: connect
[9/07/15 19:28:46:188 EST] 00000088 SystemErr     R java.net.ConnectException: Connection refused: connect
    at java.net.PlainSocketImpl.socketConnect(Native Method)
    at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:336)
    at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:201)
    at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:188)
    at java.net.Socket.connect(Socket.java:478)
    at sun.reflect.GeneratedMethodAccessor187.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java(Compiled Code))
    at java.lang.reflect.Method.invoke(Method.java(Compiled Code))
    at org.apache.commons.httpclient.protocol.ReflectionSocketFactory.createSocket(ReflectionSocketFactory.java:140)
    at org.apache.commons.httpclient.protocol.DefaultProtocolSocketFactory.createSocket(DefaultProtocolSocketFactory.java:125)
    at org.apache.commons.httpclient.HttpConnection.open(HttpConnection.java:707)
    at org.apache.commons.httpclient.HttpMethodDirector.executeWithRetry(HttpMethodDirector.java:387)
    at org.apache.commons.httpclient.HttpMethodDirector.executeMethod(HttpMethodDirector.java:171)
    at org.apache.commons.httpclient.HttpClient.executeMethod(HttpClient.java:397)
    at org.apache.commons.httpclient.HttpClient.executeMethod(HttpClient.java:323)

有人可以建议我可以调整什么或不同的建议,以允许我测试连接超时吗?

编辑

这是我正在尝试测试的代码...

    HttpClient client = new HttpClient();           
    HttpConnectionManagerParams httpConnectionManagerParams = client.getHttpConnectionManager().getParams();        
    httpConnectionManagerParams.setConnectionTimeout(45000);
    httpConnectionManagerParams.setSoTimeout(45000);
    httpConnectionManagerParams.setTcpNoDelay(false);

    // Create a method instance.
    GetMethod method = new GetMethod(url);
    HttpMethodParams httpMethodParams = method.getParams();

    // no retries
    httpMethodParams.setParameter(
            HttpMethodParams.RETRY_HANDLER,
            new DefaultHttpMethodRetryHandler(0, false));
    httpMethodParams.setSoTimeout(45000);

    try {
        // Execute the method.  
        int statusCode = client.executeMethod(method);      

        // Read the response body.
        byte[] responseBody = method.getResponseBody();
        jsonResponse = new String(
                new String(responseBody).getBytes(JsonConstants.DEFAULT_CHARSET), JsonConstants.DEFAULT_CHARSET);

    } catch (HttpException e) {
        System.err.println("HttpException " + e.getMessage());  
        e.printStackTrace();

    } catch (IOException e) {
        System.err.println("IOException " + e.getMessage());
        e.printStackTrace();

    } finally {
        // Release the connection.
        method.releaseConnection();
    }

谢谢

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回答 1

Stack Overflow用户

回答已采纳

发布于 2015-07-09 19:27:18

为什么不使用模拟测试呢?我想它是目前最好的模拟工具之一:JMockit。例如,您可以模拟HttpClient类并抛出connectionTimeOutException (或者测试代码所真正需要的任何东西)。

我仍然不清楚,当超时发生时会发生什么,从你发送的代码。它会抛出异常吗?当它发生时,您的代码如何识别它?

请看一下。如果你需要更多的帮助,给我一个呼喊=]

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/31313881

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