如何在Symfony 4中创建“更新”表单？
如何在Symfony 4中创建“更新”表单？
提问于 2018-08-09 03:14:39
使用此表单，我想要更新我的数据库条目：
myController.php
public function index($id, $slug, Request $request, UserPasswordEncoderInterface $passwordEncoder)
{
$item = new User();
$item= $this->getDoctrine()->getRepository(User::class)->find($id);
$form = $this->createFormBuilder($item)
->add('username', TextType::class, array('attr' => array('class' => 'form-control')))
->add('email', EmailType::class, array('attr' => array('class' => 'form-control')))
->add('is_active', HiddenType::class)
->add('plainPassword', RepeatedType::class, array('type' => PasswordType::class,'invalid_message' => 'The password fields must match.','options' => array('attr' => array('class' => 'password-field')),'required' => true,'first_options' => array('label' => 'Passwort', 'attr' => array('class' => 'form-control')),'second_options' => array('label' => 'Passwort wiederholen', 'attr' => array('class' => 'form-control')),))
->add('cancel', ButtonType::class, array('label' => 'Cancel','attr' => array('class' => 'cancel form-btn btn btn-default pull-right close_sidebar close_h')))
->add('update', SubmitType::class, array('label' => 'Update','attr' => array('class' => 'form-btn btn btn-info pull-right','style' => 'margin-right:5px')))
->getForm();
$form->handleRequest($request);
if($form->isSubmitted() && $form->isValid()) {
$entityManager = $this->getDoctrine()->getManager();
$entityManager->flush();
return $this->redirectToRoute('pages', array(
'slug' => $slug,
));
}
return $this->render('form.html.twig', ['form' => $form->createView()]);
}form.html.twig：
{{ form_start(form) }}
<div>
{{ form_label(form.username) }}
{{ form_widget(form.username) }}
{{ form_errors(form.username) }}
{{ form_help(form.username) }}
</div>
<div>
{{ form_label(form.email) }}
{{ form_widget(form.email) }}
{{ form_errors(form.email) }}
{{ form_help(form.email) }}
</div>
<div>
{{ form_widget(form.is_active) }}
{{ form_errors(form.is_active) }}
{{ form_help(form.is_active) }}
</div>
<div>
{{ form_label(form.plainPassword.first) }}
{{ form_widget(form.plainPassword.first) }}
<div class="text-red">{{ form_errors(form.plainPassword.first) }}</div>
{{ form_help(form.plainPassword.first) }}
</div>
<div>
{{ form_label(form.plainPassword.second) }}
{{ form_widget(form.plainPassword.second) }}
<div class="text-red">{{ form_errors(form.plainPassword.second) }}</div>
{{ form_help(form.plainPassword.second) }}
</div>
{{ form_end(form) }}但是，当我编辑表单中的用户名并单击"Update“时，我会收到错误消息
插入成员(用户名，密码，电子邮件，is_active)
(?，？)时发生异常参数"cat2"，"123"，"cat@cat.de"，"1"：
SQLSTATE23000:完整性约束冲突: 1062键“”UNIQ_12A0D2FFE7927C74“”的条目“”cat@cat.de“”重复
实际上，我希望SQL进行更新，而不是插入...
回答 1
Stack Overflow用户
回答已采纳
发布于 2018-08-09 04:58:13
您需要从UserRepository::find($id)加载用户
use App\Repository\UserRepository;
// ...
class MyController
{
public function index($id, $slug,
Request $request,
UserPasswordEncoderInterface $passwordEncoder,
UserRepository $userRepository)
{
$item = $userRepository->find($id);
if(NULL === $item) {
throw $this->createNotFoundException('could not find this user.');
}
$form = $this->createFormBuilder($item)
// ...
}
// ...
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51754096
复制相关文章
相似问题