我有包含paramiko和ssh的python脚本,如下所示
import paramiko
# setup ssh connection this works. no problem.
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
conn = ssh.connect(MACHINEIP, username=ROOTUSER, password=ROOTUSER_PASSWORD, port=22)
# This first ssh exec works perfect.
(sshin1, sshout1, ssherr1) = ssh.exec_command(cmd1)
# When I print the output of 2nd and 3rd ssh exec, I get output saying of channel open
(sshin2, sshout2, ssherr2) = ssh.exec_command(cmd2)
print sshout2
(sshin3, sshout3, ssherr3) = ssh.exec_command(cmd3)
print sshout3
当多次使用exec_command收集输出时,输出中的通道打开消息:
<paramiko.ChannelFile from <paramiko.Channel 2 (open) window=2097152
-> <paramiko.Transport at 0x1d42bd0L (cipher aes128-ctr, 128 bits)
(active; 1 open channel(s))>>>
<paramiko.ChannelFile from <paramiko.Channel 6 (open) window=2097152
-> <paramiko.Transport at 0x1d42bd0L (cipher aes128-ctr, 128 bits)
(active; 2 open channel(s))>>>
如何关闭此打开的通道?或任何解决方案?我使用的是python 2.7。
发布于 2014-01-07 23:11:58
应该作为sshout.read()
使用,而我只在打印时使用了sshout
。
https://stackoverflow.com/questions/20951690
复制相似问题