我正在使用一个函数,它应该将结果行作为一个关联数组,但它不会得到我,因为它根据主持人的指示从mysql更改为mysqli。
我究竟做错了什么
function dbquery($link,$query) {
$result = mysqli_query($link, $query );
if (!$result) {
echo mysqli_connect_error();
return false;
} else {
return($result);
}
mysqli_close($link);
}
连接数据库的功能
function dbconnect($db_host, $db_user, $db_pass, $db_name) {
global $db_connect;
$db_connect = mysqli_connect($db_host, $db_user, $db_pass);
$db_select = mysqli_select_db($db_connect, $db_name);
if (!$db_connect) {
die("<div style='font-family:Verdana;font-size:11px;text-align:center;'><b>Unable to establish connection to MySQL</b><br />".mysqli_connect_error()." : ".mysqli_connect_error()."</div>");
} elseif (!$db_select) {
die("<div style='font-family:Verdana;font-size:11px;text-align:center;'><b>Unable to select MySQL database</b><br />".mysqli_connect_error($db_name)." : ".mysqli_connect_error()."</div>");
}
}
$link = dbconnect($db_host, $db_user, $db_pass, $db_name);
哪里不对 ??
通知:未定义指数:SITEURL /home/sfera/public_html/locale/Polish-utf8/global.php上线 132 通知:未定义指数:SITEURL /home/sfera/public_html/locale/Polish-utf8/global.php上线 140 通知:未定义指数:SITEURL /home/sfera/public_html/locale/Polish-utf8/global.php上线 147
您知道如何从语言环境中删除此错误错误。我会告诉你,你知道发生了什么
$locale['global_441'] = "Your account on ".$settings['sitename']."has been banned";
$locale['global_442'] = "Hello [USER_NAME],\n
Your account on ".$settings['sitename']." was caught posting too many items to the system in very short time from the IP ".USER_IP.", and have therefor been banned. This is done to prevent bots from submitting spam messages in rapid succession.\n
Please contact the site administrator at ".$settings['siteemail']." to have your account restored or report if this was not you causing this security ban.\n
".$settings['siteusername'];
// Lifting of suspension
$locale['global_450'] = "Suspension automatically lifted by system";
$locale['global_451'] = "Suspension lifted at ".$settings['sitename'];
$locale['global_452'] = "Hello USER_NAME,\n
The suspension of your account at ".$settings['siteurl']." has been lifted. Here are your login details:\n
Username: USER_NAME
Password: Hidden for security reasons\n
If you have forgot your password you can reset it via the following link: LOST_PASSWORD\n\n
Regards,\n
".$settings['siteusername'];
$locale['global_453'] = "Hello USER_NAME,\n
The suspension of your account at ".$settings['siteurl']." has been lifted.\n\n
Regards,\n
".$settings['siteusername'];
$locale['global_454'] = "Account reactivated at ".$settings['sitename'];
$locale['global_455'] = "Hello USER_NAME,\n
Last time you logged in your account was reactivated at ".$settings['siteurl']." and your account is no longer marked as inactive.\n\n
Regards,\n
虽然我在功能上有它,但它让我从基地开始论证
//从数据库中获取站点设置并将它们存储在$ settings变量中
$settings = dbarray(dbquery($link,"SELECT * FROM ".$db_prefix."setting"));
所以这是但是语言环境不想阅读它们
发布于 2018-08-28 10:54:51
mysqli_connect_error()
应该只用于报告期间发生的错误mysqli_connect()
。如果在执行查询时出错,则应使用mysqli_error()
该错误。
而且,你在打电话mysqli_close($link);
。这从未执行过,因为if
语句的两个分支都是从函数返回的。但是你不应该关闭这个函数中的链接,你很可能想要为其他查询使用相同的链接。
所以功能应该是:
function dbquery($link,$query) {
$result = mysqli_query($link, $query );
if (!$result) {
echo mysqli_error($link);
return false;
} else {
return($result);
}
}
同样,dbconnect()
应该mysqli_error()
在报告失败时使用mysqli_select_db()
。它还需要返回连接而不是设置全局变量。
function dbconnect($db_host, $db_user, $db_pass, $db_name) {
$db_connect = mysqli_connect($db_host, $db_user, $db_pass);
$db_select = mysqli_select_db($db_connect, $db_name);
if (!$db_connect) {
die("<div style='font-family:Verdana;font-size:11px;text-align:center;'><b>Unable to establish connection to MySQL</b><br />".mysqli_connect_error()." : ".mysqli_connect_error()."</div>");
} elseif (!$db_select) {
die("<div style='font-family:Verdana;font-size:11px;text-align:center;'><b>Unable to select MySQL database $db_name</b><br />".mysqli_error($db_connect)." : ".mysqli_error($db_connect)."</div>");
}
return $db_connect;
}
您也可以将mysqli_connect()
和mysqli_select_db()
,作为数据库名称可以被指定为一个额外的参数mysqli_connect()
:
mysqli_connect($db_host, $db_user, $db_pass, $db_name);
发布于 2018-08-28 11:53:14
我使用这个功能
$result = dbquery("SELECT * FROM ".$db_prefix."product ");
$product = dbarray($result);
再次,dbquery函数
function dbquery($link,$query) {
$result = mysqli_query($link, $query );
if (!$result) {
echo mysqli_connect_error();
return false;
} else {
return($result);
}
mysqli_close($link);
}
我按你说的做了,但我还有错误
注意:未定义的变量:102行/home/sfera/public_html/funkcje.php中的db_connect 注意:未定义的变量:在第102行的/home/sfera/public_html/funkcje.php中查询 警告:mysqli_query()要求参数1为mysqli,在第102行的/home/sfera/public_html/funkcje.php中给出null 警告:include(locale // global.php):无法打开流:第164行/home/sfera/public_html/funkcje.php中没有此类文件或目录 警告:include():在/home/sfera/public_html/funkcje.php中打开'locale // global.php'以包含(include_path ='。:/ opt / alt / php70 / usr / share / pear')失败第164行 注意:未定义的变量:102行/home/sfera/public_html/funkcje.php中的db_connect 注意:未定义的变量:在第102行的/home/sfera/public_html/funkcje.php中查询 警告:mysqli_query()要求参数1为mysqli,在第102行的/home/sfera/public_html/funkcje.php中给出null
我这样做了。
function dbquery() {
$result = mysqli_query($db_connect, $query);
if (!$result) {
echo mysqli_connect_error();
return false;
} else {
return($result);
}
}
这些错误导致你无法连接到基地?
他这样称呼它
$result = dbquery($link,"SELECT tac.kategoria, tac.tytul, tac.tytul, tac.images, tac.cena, tac.product_id, tac.min, tac.max, tac.promocja,
tac.pierwsza_pozycja, tac.druga_pozycja, tac.cena,
tac.opcja, tac.cena_1, tac.opcja_1, tac.cena_2,
tac.opcja_2,tac.cena_3, tac.opcja_3, tac.cena_4,
tac.opcja_4, tac.cena_5, tac.opcja_5, tac.cena_6,
tac.opcja_6, tac.cena_7, tac.opcja_7, tac.cena_8,
tac.opcja_8, tac.cena_9, tac.opcja_9 , tac.kwota_dodatku,
ta.przyrostek_categori, wt.cena_towaru, wt.cena_towaru_1, wt.min_towar, wt.cena_min_towaru
FROM ".$db_prefix."product tac
INNER JOIN ".$db_prefix."category ta ON tac.kategoria=ta.przyrostek_categori
LEFT JOIN ".$db_prefix."wybrany_towar wt ON wt.wybrany_towar_id=tac.product_id
WHERE kategoria='".$_GET['kategoria']."' AND product_id='".$_GET['product_id']."'");
$product = dbarray($result);
https://stackoverflow.com/questions/-100008821
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