blocks|key|4064295|text|我尝试在编辑时执行此操作，但我将函数内部的console.log(+true+)替换为return+true。这解决了我的问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4064296|请在此处再次更正代码：|4064297|function+checkForNumber(arr,+num)+{
++if+(arr[0]+===+num)+{
+++++//console.log(true)+removed
+++++return+true
+++}+else+if+(arr.slice(-1)[0]+===+num)+{
+++++//console.log(true)+removed
+++++return+true
+++}+else
++return+false;
+}
console.log(checkForNumber([4,+2,+5,+3],+4)+===+true);
console.log(checkForNumber([4,+2,+5,+3],+3)+===+true);
console.log(checkForNumber([4,+2,+5,+3],+2)+===+false);
console.log(checkForNumber([4,+2,+5,+3],+13)+===+false);|code-block|syntax|javascript|4064298|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<p>I tried doing this while editing, but i replaced the console.log(true) inside the function with return true. This solved my question.</p>

<p>Correct Code here again:</p>

<pre><code>function checkForNumber(arr, num) {
  if (arr[0] === num) {
     //console.log(true) removed
     return true
   } else if (arr.slice(-1)[0] === num) {
     //console.log(true) removed
     return true
   } else
  return false;
 }
console.log(checkForNumber([4, 2, 5, 3], 4) === true);
console.log(checkForNumber([4, 2, 5, 3], 3) === true);
console.log(checkForNumber([4, 2, 5, 3], 2) === false);
console.log(checkForNumber([4, 2, 5, 3], 13) === false);
</code></pre>


blocks|key|4063133|text|这是我在评论中建议的完全实现的解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4063134|​|4063135|function+checkForNumber(arr,+num)+{
++if+(arr[0]+===+num+%7C%7C+arr[arr.length+-+1]+===+num)+{
++++return+true
++}+else
++++return+false;
}

console.log(checkForNumber([4,+2,+5,+3],+4));
console.log(checkForNumber([4,+2,+5,+3],+3));
console.log(checkForNumber([4,+2,+5,+3],+2));
console.log(checkForNumber([4,+2,+5,+3],+13));
console.log(checkForNumber([4,+2,+5,+4],+4));|code-block|syntax|javascript|4063136|4063137|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>Here is the solution fully implemented that I suggested in the comments.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>function checkForNumber(arr, num) {
  if (arr[0] === num || arr[arr.length - 1] === num) {
    return true
  } else
    return false;
}

console.log(checkForNumber([4, 2, 5, 3], 4));
console.log(checkForNumber([4, 2, 5, 3], 3));
console.log(checkForNumber([4, 2, 5, 3], 2));
console.log(checkForNumber([4, 2, 5, 3], 13));
console.log(checkForNumber([4, 2, 5, 4], 4));</code></pre>
</div>
</div>
</p>


blocks|key|4063189|text|我觉得这就足够了，对吧？干杯!|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4063190|function+checkForNumber(arr,+num)
{
++++//+for+OR
++++return+((arr[0]+===+num)+%7C%7C+(arr[arr.length-1]+===+num));
++++//+for+AND
++++//+return+((arr[0]+===+num)+&&+(arr[arr.length-1]+===+num));
}
console.log(checkForNumber([4,+2,+5,+3],+4)+===+true);
console.log(checkForNumber([3,+2,+5,+4],+3)+===+true);
console.log(checkForNumber([0,+4,+4,+8],+2)+===+false);
console.log(checkForNumber([4,+2,+5,+3],+13)+===+false);|code-block|syntax|javascript|4063191|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>I think that this is enough, right?
Cheers!</p>

<pre><code>function checkForNumber(arr, num)
{
    // for OR
    return ((arr[0] === num) || (arr[arr.length-1] === num));
    // for AND
    // return ((arr[0] === num) &amp;&amp; (arr[arr.length-1] === num));
}
console.log(checkForNumber([4, 2, 5, 3], 4) === true);
console.log(checkForNumber([3, 2, 5, 4], 3) === true);
console.log(checkForNumber([0, 4, 4, 8], 2) === false);
console.log(checkForNumber([4, 2, 5, 3], 13) === false);
</code></pre>


blocks|key|4063219|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4063220|function+checkForNumber(arr,+num)+{
++return+arr[0]+===+num+%7C%7C+arr[arr.length+-+1]+===+num;
}
console.log(checkForNumber([4,+2,+5,+3],+4)+===+true);
console.log(checkForNumber([4,+2,+5,+3],+3)+===+true);
console.log(checkForNumber([4,+2,+5,+3],+2)+===+false);
console.log(checkForNumber([4,+2,+5,+3],+13)+===+false);|code-block|syntax|javascript|4063221|4063222|if+(condition)+return+true和类似的是反模式。如果函数是谓词(即返回布尔值)，则只返回逻辑运算的结果。|offset|length|style|CODE|4063223|entityMap^0|0|0|0|0|Q|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|S|8|@$J|T|K|U|L|M]]|9|@]|A|$]]|$1|N|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|O|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>function checkForNumber(arr, num) {
  return arr[0] === num || arr[arr.length - 1] === num;
}
console.log(checkForNumber([4, 2, 5, 3], 4) === true);
console.log(checkForNumber([4, 2, 5, 3], 3) === true);
console.log(checkForNumber([4, 2, 5, 3], 2) === false);
console.log(checkForNumber([4, 2, 5, 3], 13) === false);</code></pre>
</div>
</div>
</p>

<p><code>if (condition) return true</code> and similar are anti-patterns. If the function is a predicate (i.e. returning a boolean value), just return the result of the logical operation.</p>


<p>I am trying to write a function to check if an array contains a specific number at the first or last position of the array.</p>

<p>All of the <code>console.log</code> examples there should print <code>true</code>. The way its printing I don't think I should be writing to <code>console.log</code> in my function. I can't get them all to show <code>true</code>.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>function checkForNumber(arr, num) {
  if (arr[0] === num) {
    //console.log(true) removed
    return true
  } else if (arr.slice(-1)[0] === num) {
    //console.log(true) removed
    return true
  } else
    return false;
}
console.log(checkForNumber([4, 2, 5, 3], 4) === true);
console.log(checkForNumber([4, 2, 5, 3], 3) === true);
console.log(checkForNumber([4, 2, 5, 3], 2) === false);
console.log(checkForNumber([4, 2, 5, 3], 13) === false);</code></pre>
</div>
</div>
</p>


Function to verify if first OR last item in array are equal to a certain number

我正在尝试编写一个函数来检查数组的第一个或最后一个位置是否包含特定的数字。那里的所有console.log示例都应该输出true。它的打印方式，我不认为我应该在我的函数中写入console.log。我不能让他们都给true看。​function checkForNumber(arr, num) {  if (arr[0...

问用于验证数组中的第一项或最后一项是否等于某个数字的函数
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问用于验证数组中的第一项或最后一项是否等于某个数字的函数EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问用于验证数组中的第一项或最后一项是否等于某个数字的函数
EN