根据我对Python的ctypes
的理解,ctypes.sizeof(...)
应该返回传入的结构的大小(以字节为单位),就像使用C的sizeof
操作符一样。然而,我总是得到0
的结果:
$ python
Python 2.7.12 (default, Dec 4 2017, 14:50:18)
[GCC 5.4.0 20160609] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import ctypes
>>> class testStruct(ctypes.Structure):
... _fields = [
... ("testField", ctypes.c_uint*4)
... ]
...
>>> ctypes.sizeof(testStruct)
0
>>> test = testStruct()
>>> ctypes.sizeof(test)
0
为什么会发生这种情况?
发布于 2018-07-28 06:10:56
你忘了给_fields
加上下划线_
,它应该是_fields_
。
import ctypes
class testStruct(ctypes.Structure):
# NOT just _fields:
_fields_ = [
("testField", ctypes.c_uint*4)
]
print(ctypes.sizeof(testStruct))
test = testStruct()
print(ctypes.sizeof(test))
输出:
16
16
https://stackoverflow.com/questions/51566069
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