blocks|key|1419773|text|你试过这个类的__name__+attribute了吗？ie+type(x).__name__会给你类名，我想这就是你想要的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1419774|>>>+import+itertools
>>>+x+=+itertools.count(0)
>>>+type(x).__name__
'count'|code-block|syntax|javascript|1419775|如果您仍在使用Python2，请注意上述方法仅适用于new-style+classes+(在Python+3%2B中，所有类都是“新风格”的类)。您的代码可能会使用一些旧式的类。以下方法适用于这两种情况：|1419776|x.__class__.__name__|1419777|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/library/stdtypes.html#definition.__name__|1|https://wiki.python.org/moin/NewClassVsClassicClass^0|7|8|V|G|7|I|0|0|0|Q|H|1|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|G|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|17|8|@]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|M|3|N|5|H|7|1B|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]]]

Have you tried the <a href="https://docs.python.org/library/stdtypes.html#definition.__name__" rel="noreferrer"><code>__name__</code> attribute</a> of the class? ie <code>type(x).__name__</code> will give you the name of the class, which I think is what you want.

<pre><code>&gt;&gt;&gt; import itertools
&gt;&gt;&gt; x = itertools.count(0)
&gt;&gt;&gt; type(x).__name__
'count'
</code></pre>

If you're still using Python 2, note that the above method works with <a href="https://wiki.python.org/moin/NewClassVsClassicClass" rel="noreferrer">new-style classes</a> only (in Python 3+ all classes are "new-style" classes). Your code might use some old-style classes. The following works for both:

<pre><code>x.__class__.__name__
</code></pre>

blocks|key|1419820|text|是否要将类的名称作为字符串？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1419821|instance.__class__.__name__|code-block|syntax|javascript|1419822|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Do you want the name of the class as a string?

<pre><code>instance.__class__.__name__
</code></pre>

blocks|key|1419692|text|type()？|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1419693|>>>+class+A:
...+++++def+whoami(self):
...+++++++++print(type(self).__name__)
...
>>>
>>>+class+B(A):
...+++++pass
...
>>>
>>>
>>>+o+=+B()
>>>+o.whoami()
'B'
>>>|code-block|syntax|javascript|1419694|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/functions.html#type^0|0|6|0|6|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

<a href="https://docs.python.org/3/library/functions.html#type" rel="noreferrer"><code>type()</code></a> ?
<pre><code>&gt;&gt;&gt; class A:
... def whoami(self):
... print(type(self).__name__)
...
&gt;&gt;&gt;
&gt;&gt;&gt; class B(A):
... pass
...
&gt;&gt;&gt;
&gt;&gt;&gt;
&gt;&gt;&gt; o = B()
&gt;&gt;&gt; o.whoami()
'B'
&gt;&gt;&gt;
</code></pre>

blocks|key|1634763|text|在Python+2中，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1634764|type(instance).__name__+!=+instance.__class__.__name__
#+if+class+A+is+defined+like
class+A():
+++...

type(instance)+==+instance.__class__
#+if+class+A+is+defined+like
class+A(object):
++...|code-block|syntax|javascript|1634765|示例：|1634766|>>>+class+aclass(object):
...+++pass
...
>>>+a+=+aclass()
>>>+type(a)
<class+'__main__.aclass'>
>>>+a.__class__
<class+'__main__.aclass'>
>>>
>>>+type(a).__name__
'aclass'
>>>
>>>+a.__class__.__name__
'aclass'
>>>


>>>+class+bclass():
...+++pass
...
>>>+b+=+bclass()
>>>
>>>+type(b)
<type+'instance'>
>>>+b.__class__
<class+__main__.bclass+at+0xb765047c>
>>>+type(b).__name__
'instance'
>>>
>>>+b.__class__.__name__
'bclass'
>>>|1634767|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

In Python 2,
<pre><code>type(instance).__name__ != instance.__class__.__name__
# if class A is defined like
class A():
 ...

type(instance) == instance.__class__
# if class A is defined like
class A(object):
 ...
</code></pre>
Example:
<pre><code>&gt;&gt;&gt; class aclass(object):
... pass
...
&gt;&gt;&gt; a = aclass()
&gt;&gt;&gt; type(a)
&lt;class '__main__.aclass'&gt;
&gt;&gt;&gt; a.__class__
&lt;class '__main__.aclass'&gt;
&gt;&gt;&gt;
&gt;&gt;&gt; type(a).__name__
'aclass'
&gt;&gt;&gt;
&gt;&gt;&gt; a.__class__.__name__
'aclass'
&gt;&gt;&gt;


&gt;&gt;&gt; class bclass():
... pass
...
&gt;&gt;&gt; b = bclass()
&gt;&gt;&gt;
&gt;&gt;&gt; type(b)
&lt;type 'instance'&gt;
&gt;&gt;&gt; b.__class__
&lt;class __main__.bclass at 0xb765047c&gt;
&gt;&gt;&gt; type(b).__name__
'instance'
&gt;&gt;&gt;
&gt;&gt;&gt; b.__class__.__name__
'bclass'
&gt;&gt;&gt;
</code></pre>

blocks|key|1419885|text|问得好。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1419886|这是一个基于GHZ的简单示例，可能会对某些人有所帮助：|1419887|>>>+class+person(object):
++++++++def+init(self,name):
++++++++++++self.name=name
++++++++def+info(self)
++++++++++++print+"My+name+is+{0},+I+am+a+{1}".format(self.name,self.__class__.__name__)
>>>+bob+=+person(name='Robert')
>>>+bob.info()
My+name+is+Robert,+I+am+a+person|code-block|syntax|javascript|1419888|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Good question.

Here's a simple example based on GHZ's which might help someone:

<pre><code>&gt;&gt;&gt; class person(object):
 def init(self,name):
 self.name=name
 def info(self)
 print "My name is {0}, I am a {1}".format(self.name,self.__class__.__name__)
&gt;&gt;&gt; bob = person(name='Robert')
&gt;&gt;&gt; bob.info()
My name is Robert, I am a person
</code></pre>

blocks|key|1420000|text|除了获取特殊的__name__属性之外，您可能会发现自己需要用于给定类/函数的qualified+name。这是通过获取类型__qualname__来完成的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1420001|在大多数情况下，它们是完全相同的，但是，当处理嵌套类/方法时，它们在您得到的输出中是不同的。例如：|1420002|class+Spam:
++++def+meth(self):
++++++++pass
++++class+Bar:
++++++++pass

>>>+s+=+Spam()
>>>+type(s).__name__+
'Spam'
>>>+type(s).__qualname__
'Spam'
>>>+type(s).Bar.__name__+++++++#+type+not+needed+here
'Bar'
>>>+type(s).Bar.__qualname__+++#+type+not+needed+here+
'Spam.Bar'
>>>+type(s).meth.__name__
'meth'
>>>+type(s).meth.__qualname__
'Spam.meth'|code-block|syntax|javascript|1420003|因为自省是你所追求的，所以这也是你可能想要考虑的。|1420004|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/stdtypes.html#definition.__name__|1|https://www.python.org/dev/peps/pep-3155/^0|7|8|1Q|C|7|8|0|13|E|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]|$9|16|A|17|1|18]]|E|$]]|$1|F|3|G|5|6|7|19|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1A|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1B|8|@]|D|@]|E|$]]|$1|O|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]]]

Apart from grabbing the special <a href="https://docs.python.org/3/library/stdtypes.html#definition.__name__" rel="noreferrer"><code>__name__</code></a> attribute, you might find yourself in need of the <a href="https://www.python.org/dev/peps/pep-3155/" rel="noreferrer">qualified name</a> for a given class/function. This is done by grabbing the types <code>__qualname__</code>.

In most cases, these will be exactly the same, but, when dealing with nested classes/methods these differ in the output you get. For example:

<pre><code>class Spam:
 def meth(self):
 pass
 class Bar:
 pass

&gt;&gt;&gt; s = Spam()
&gt;&gt;&gt; type(s).__name__ 
'Spam'
&gt;&gt;&gt; type(s).__qualname__
'Spam'
&gt;&gt;&gt; type(s).Bar.__name__ # type not needed here
'Bar'
&gt;&gt;&gt; type(s).Bar.__qualname__ # type not needed here 
'Spam.Bar'
&gt;&gt;&gt; type(s).meth.__name__
'meth'
&gt;&gt;&gt; type(s).meth.__qualname__
'Spam.meth'
</code></pre>

Since introspection is what you're after, this is always you might want to consider.

blocks|key|1634930|text|获取实例类名：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1634931|type(instance).__name__|code-block|syntax|javascript|1634932|或|1634933|instance.__class__.__name__|1634934|两者都是一样的|1634935|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

To get instance classname:

<pre class="lang-py prettyprint-override"><code>type(instance).__name__
</code></pre>

or

<pre class="lang-py prettyprint-override"><code>instance.__class__.__name__
</code></pre>

both are the same

How do I find out a name of class that created an instance of an object in Python if the function I am doing this from is the base class of which the class of the instance has been derived?

Was thinking maybe <a href="https://docs.python.org/2/library/inspect.html" rel="noreferrer" title="inspect — Inspect live objects">the inspect module</a> might have helped me out here, but it doesn't seem to give me what I want. And short of parsing the <code>__class__</code> member, I'm not sure how to get at this information.

Getting the class name of an instance?

Python

如果我执行此操作的函数是派生实例的基类，我如何在Python中找到创建对象实例的类名？我在想也许可以帮到我，但它似乎没有给我想要的东西。由于没有解析__class__成员，我不确定如何获取这些信息。

问获取实例的类名？
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问获取实例的类名？EN

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问获取实例的类名？
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