blocks|key|4096348|text|第一个问题的答案是这个链接。getting+start+Cgi+programmin|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4096349|第二个问题的答案是:你应该使用多线程编程。|4096350|如果您在模块test2中有示例函数...|4096351|#in+test1.py
import+threading
import+test2
T1+=+threading.Thread(test2.sample(object))
T1.start()|code-block|syntax|javascript|4096352|回答你的第三个问题：|4096353|然后，您可以在站点的路径中创建一个cgi文件所在的文件夹，或者配置某些目录以将某些文件类型作为cgi脚本进行处理。这在上面的cgi文档中描述得很好，但本质上是为了让cgi文件夹中的所有文件都被执行，您将使用以下apache2：|4096354|+++++Options+ExecCGI+++++++++SetHandler+cgi-script+++++|4096355|要允许.py文件作为脚本在特定文件夹中执行，您可以使用以下配置文件：|4096356|<Directory+/srv/www/yoursite/public_html>
++++Options+%2BExecCGI
++++AddHandler+cgi-script+.py
</Directory>|4096357|一旦你有了它，如果你运行的是python3，你可以创建一个像这样的python脚本，并把它放在为cgi配置的任何文件夹中：|4096358|#!/usr/bin/env+python
#+-*-+coding:+UTF-8+-*-#+enable+debugging
import+cgitb
cgitb.enable()++++print("Content-Type:+text/html;charset=utf-8")
print()++++print("Hello+World!")|4096359|entityMap|0|LINK|mutability|MUTABLE|url|https://www.w3resource.com/python/cgi-programming.php^0|E|S|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@$A|19|B|1A|1|1B]]|C|$]]|$1|D|3|E|5|6|7|1C|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|1D|8|@]|9|@]|C|$]]|$1|H|3|I|5|J|7|1E|8|@]|9|@]|C|$K|L]]|$1|M|3|N|5|6|7|1F|8|@]|9|@]|C|$]]|$1|O|3|P|5|6|7|1G|8|@]|9|@]|C|$]]|$1|Q|3|R|5|J|7|1H|8|@]|9|@]|C|$K|L]]|$1|S|3|T|5|6|7|1I|8|@]|9|@]|C|$]]|$1|U|3|V|5|J|7|1J|8|@]|9|@]|C|$K|L]]|$1|W|3|X|5|6|7|1K|8|@]|9|@]|C|$]]|$1|Y|3|Z|5|J|7|1L|8|@]|9|@]|C|$K|L]]|$1|10|3|-4|5|6|7|1M|8|@]|9|@]|C|$]]]|11|$12|$5|13|14|15|C|$16|17]]]]

The answer to your first question is this link .<a href="https://www.w3resource.com/python/cgi-programming.php" rel="nofollow noreferrer">getting start Cgi programmin</a>

The answer to your second question: You should use multi-threaded programming.
 If you have sample function in module test2 ...

<pre><code>#in test1.py
import threading
import test2
T1 = threading.Thread(test2.sample(object))
T1.start()
</code></pre>

Answer your third question: 
Then you can either make a folder in your site's path where your cgi files will live, or configure certain directories to handle certain file types as cgi scripts.
This is described well in the apache2 doc above, but essentially you to make all files in a cgi folder be executed, you would use this conf:


 Options ExecCGI
 SetHandler cgi-script
 

and to allow .py files to be executed as scripts in a particular folder you would use this conf:

<pre><code>&lt;Directory /srv/www/yoursite/public_html&gt;
 Options +ExecCGI
 AddHandler cgi-script .py
&lt;/Directory&gt;
</code></pre>

Once you have that, if you're running python 3, you can make a python script like this one, and stick it in whichever folder is configured for cgi:

<pre><code>#!/usr/bin/env python
# -*- coding: UTF-8 -*-# enable debugging
import cgitb
cgitb.enable() print("Content-Type: text/html;charset=utf-8")
print() print("Hello World!")
</code></pre>

blocks|key|4096417|text|谢谢，这是一个很好的回答！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4096418|我只是在我的脚本test1.py中添加了这段代码(在test2.py中没有函数，只是原始代码)：|4096419|..。导入test2+cgitb.enable()|4096420|T1+=+threading.Thread(test2)+T1.start()|4096421|..。|4096422|然而，网页仍然永远等待，尽管我注意到test2确实是由线程启动的……你知道如何让网页显示一些东西而不是等待吗？|4096423|请注意，我也尝试过：|4096424|pid+=+os.fork()
#if+pid==0+then+we+are+in+the+child+process
if(pid==0):
++++T1+=+threading.Thread(test2)
++++T1.start()
++++#i+would+hope+that+here+the+child+process+is+detached+from+making+wait+the+CGI!!+but+no
else:
++++print('Content-type:+text/html\n\n')
++++print('<h1>Python+Script+Test</h1>')
++++form+=+cgi.FieldStorage()
++++tempThVal+=+form['tempThresh'].value
++++print('Temperature+threshold=+'+%2B+tempThVal)|code-block|syntax|javascript|4096425|但该死的浏览器仍在等待它的结束！！|4096426|entityMap^0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|Y|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|Z|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|10|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|11|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|12|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|13|8|@]|9|@]|A|$Q|R]]|$1|S|3|T|5|6|7|14|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

thanks this is a great answer!

I just added this to my script test1.py (atm no function in test2.py just raw code):

[...]
import test2
cgitb.enable()

T1 = threading.Thread(test2)
T1.start()

[...]

However the webpage still waits forever although i noticed that the test2 is indeed launched by the thread...
do you have an idea how to make the webpage display something instead of waiting?

Please note that i have also tried that:

<pre><code>pid = os.fork()
#if pid==0 then we are in the child process
if(pid==0):
 T1 = threading.Thread(test2)
 T1.start()
 #i would hope that here the child process is detached from making wait the CGI!! but no
else:
 print('Content-type: text/html\n\n')
 print('&lt;h1&gt;Python Script Test&lt;/h1&gt;')
 form = cgi.FieldStorage()
 tempThVal = form['tempThresh'].value
 print('Temperature threshold= ' + tempThVal)
</code></pre>

But still the damned browser is waiting for it to finish!!

blocks|key|4097981|text|要解决这个问题，您可以将您自己的解决方案与我的答案结合起来，以获得正确的答案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4097982|#in+test1.py

class+my_thread(threading.Thread):
++++def+__init__(self):
++++++++super().__init__()

++++def+run(self):
++++++++p+=+subprocess.Popen([sys.executable,+'/var/www/cgi-bin/test2.py'],
+++++++++++++++++stdout=subprocess.PIPE,+stderr=subprocess.STDOUT)
++++++++########################
++++++++#or+your+test2+statment#
++++++++########################
pid+=+os.fork()
#if+pid==0+then+we+are+in+the+child+process
if(pid==0):
++++T1+=+my_thread()
++++T1.start()
#i+would+hope+that+here+the+child+process+is+detached+from+making+wait+the+CGI!!+but+
no
else:
+++print('Content-type:+text/html\n\n')
+++print('<h1>Python+Script+Test</h1>')
+++form+=+cgi.FieldStorage()
+++tempThVal+=+form['tempThresh'].value
+++print('Temperature+threshold=+'+%2B+tempThVal)|code-block|syntax|javascript|4097983|我在Django框架中使用了这种方法来解决这个问题|4097984|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

To solve this problem, you can combine your own solution with my answer to get the right answer.

<pre><code>#in test1.py

class my_thread(threading.Thread):
 def __init__(self):
 super().__init__()

 def run(self):
 p = subprocess.Popen([sys.executable, '/var/www/cgi-bin/test2.py'],
 stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
 ########################
 #or your test2 statment#
 ########################
pid = os.fork()
#if pid==0 then we are in the child process
if(pid==0):
 T1 = my_thread()
 T1.start()
#i would hope that here the child process is detached from making wait the CGI!! but 
no
else:
 print('Content-type: text/html\n\n')
 print('&lt;h1&gt;Python Script Test&lt;/h1&gt;')
 form = cgi.FieldStorage()
 tempThVal = form['tempThresh'].value
 print('Temperature threshold= ' + tempThVal)
</code></pre>

I used this method to solve this problem in the Django framework

blocks|key|4096474|text|让我来发布我的最新代码(以防你会发现什么)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4096475|#!/usr/bin/python3

import+cgi
import+cgitb
import+sys
import+subprocess
import+os
import+threading
import+test2
cgitb.enable()

class+my_thread(threading.Thread):
++++def+__init__(self):
++++++++super().__init__()

++++def+run(self):
++++++++p+=+subprocess.Popen([sys.executable,+'/var/www/cgi-bin/test2.py'],
+++++++++++++++++stdout=subprocess.PIPE,+stderr=subprocess.STDOUT)
++++++++########################
++++++++#or+your+test2+statment#
++++++++########################
pid+=+os.fork()
#if+pid==0+then+we+are+in+the+child+process
if(pid==0):
++++pid+=+os.fork()
++++if(pid==0):
++++++++T1+=+my_thread()
++++++++T1.start()
else:
+++print('Content-type:+text/html\n\n')
+++print('<h1>Python+Script+Test</h1>')
+++form+=+cgi.FieldStorage()
+++tempThVal+=+form['tempThresh'].value
+++print('Temperature+threshold=+'+%2B+tempThVal)|code-block|syntax|javascript|4096476|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

let me maybe just post my latest code (in case you might find something):

<pre><code>#!/usr/bin/python3

import cgi
import cgitb
import sys
import subprocess
import os
import threading
import test2
cgitb.enable()

class my_thread(threading.Thread):
 def __init__(self):
 super().__init__()

 def run(self):
 p = subprocess.Popen([sys.executable, '/var/www/cgi-bin/test2.py'],
 stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
 ########################
 #or your test2 statment#
 ########################
pid = os.fork()
#if pid==0 then we are in the child process
if(pid==0):
 pid = os.fork()
 if(pid==0):
 T1 = my_thread()
 T1.start()
else:
 print('Content-type: text/html\n\n')
 print('&lt;h1&gt;Python Script Test&lt;/h1&gt;')
 form = cgi.FieldStorage()
 tempThVal = form['tempThresh'].value
 print('Temperature threshold= ' + tempThVal)
</code></pre>

I have read various posts here about the problem of starting another python script inside one that is being called by a CGI i.e., I have an apache2 server running on a Raspberrypi with CGI enabled.

1) from a browser : webform data is sent to the CGI interface and it calls my python script <code>test1.py</code>

2) from <code>test1.py</code> I want to call <code>test2.py</code> (which will run forever or for whatever time needed (it updates continuously values somewhere)

3) the point is : I want the CGI script to IMMEDIATELY display some result let's say "test2 has started" on a "result webpage" AND run in background my <code>test2.py</code>

However what happends is that the webpage with the form just waits forever that my test2.py finishes!

I have tried things like:

<pre><code>p = subprocess.Popen([sys.executable, '/var/www/cgi-bin/test2.py'],
 stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
</code></pre>

But this does not work (i.e. waits for the script test2 to finish...)

Can someone help?

python CGI call new subprocess without waiting

服务器

Django

Python

我在这里读过很多关于在CGI调用的python脚本中启动另一个python脚本的问题的文章，也就是说，我有一个运行在启用CGI的Raspberrypi上的apache2服务器。1)从浏览器: webform数据被发送到CGI接口，它调用我的python脚本test1.py2)在test1.py中，我想调用test2.p...

问python CGI无需等待即可调用新子进程
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