我在使用数组实现此结果时遇到问题,我想用第一个数组中的数据更新另一个空数组,方法是省略前两行,将前三行添加到空数组的索引0中,然后将下三行也更新到第二个索引中,依此类推。我有这个数组
`$arr = [
'tqty' => 9,
'tPrice' => 18700,
'food_name_1' => 'Black Coffee',
'food_quanty_1' => 1,
'food_price_1' => 1000,
'food_name_2' => 'Sub Combo',
'food_quanty_2' => 2,
'food_price_2' => 3000
];`
我想使用这个数组数据,并以这种方式更新另一个空数组,删除前两行
$arr2 = [
0 => [
'food_name_1' => 'Black Coffee',
'food_quanty_1' => 1,
'food_price_1' => 1000
],
1 => [
'food_name_2' => 'Sub Combo',
'food_quanty_2' => 2,
'food_price_2' => 3000
]
];
到目前为止,以下是我的代码
$arr = [
'tqty' => 9,
'tPrice' => 18700,
'food_name_1' => 'Black Coffee',
'food_quanty_1' => 1,
'food_price_1' => 1000,
'food_name_2' => 'Sub Combo',
'food_quanty_2' => 2,
'food_price_2' => 3000
];
$newdat = [];
$count = 0;
$oldcount = 1;
foreach($arr as $key => $value){
if(preg_match_all('!\d+!', $key, $matches)){
if($oldcount == $matches[0][0]){
$newdat[$matches[0][0]] = [
$count => [
$key => $value
]
];
} else{
$count = 0;
$oldcount = $matches[0][0];
}
}
$count++;
}
我希望我能尽快得到帮助。谢谢
发布于 2018-06-15 06:53:14
如果我没理解错的话,
$newdata = array();
for ($i = 1; $i++;) { // Intentionally no condition set.
if (array_key_exists('food_name_' . $i, $arr)) {
$temparray = array();
$temparray['food_name_' . $i] = $arr['food_name_' . $i];
if (array_key_exists('food_quanty_' . $i, $arr)) {
$temparray['food_quanty_' . $i] = $arr['food_quanty_' . $i];
}
if (array_key_exists('food_price_' . $i, $arr)) {
$temparray['food_price_' . $i] = $arr['food_price_' . $i];
}
$newdata[] = $temparray;
} else {
break; // break out of the loop
}
}
echo "<pre>";
print_r($newdata);
echo "</pre>";
die();
发布于 2018-06-15 06:44:12
假设数组键和顺序保持一致,您可以使用array_chunk
<?php
$inArray = [
'tqty' => 9,
'tPrice' => 18700,
'food_name_1' => 'Black Coffee',
'food_quanty_1' => 1,
'food_price_1' => 1000,
'food_name_2' => 'Sub Combo',
'food_quanty_2' => 2,
'food_price_2' => 3000,
];
$outArray = [];
// Remove first 2 values.
$inArray = array_slice( $inArray, 2 );
// 'Chunk' the rest of the values.
// true preserves keys.
$outArray = array_chunk( $inArray, 3, true );
echo '<pre>' . print_r( $outArray, true ) . '</pre>';
/**
Output:
<pre>Array
(
[0] => Array
(
[food_name_1] => Black Coffee
[food_quanty_1] => 1
[food_price_1] => 1000
)
[1] => Array
(
[food_name_2] => Sub Combo
[food_quanty_2] => 2
[food_price_2] => 3000
)
)
</pre>
*/
发布于 2018-06-15 06:48:14
这是一个解决方案,它将在末尾定位_x
,以检查其数字
这个解决方案并不关心您有多少未编号的字段,或者每个编号的“行”有多少字段,它们也是基于_x
编号进行索引的。
$arr = [
'tqty' => 9,
'tPrice' => 18700,
'food_name_1' => 'Black Coffee',
'food_quanty_1' => 1,
'food_price_1' => 1000,
'food_name_2' => 'Sub Combo',
'food_quanty_2' => 2,
'food_price_2' => 3000
];
$arr2 = array();
foreach( $arr as $key => $value )
{
$explode = explode( '_', $key );
if( ctype_digit( $index = end( $explode ) ) === true)
{
if( isset( $arr2[ $index ] ) === false )
{
$arr2[ $index ] = array();
}
$arr2[ $index ][ substr( $key, 0, strlen( $key ) - 1 - strlen( $index ) ) ] = $value;
}
}
print_r( $arr2 );
输出:
Array
(
[1] => Array
(
[food_name] => Black Coffee
[food_quanty] => 1
[food_price] => 1000
)
[2] => Array
(
[food_name] => Sub Combo
[food_quanty] => 2
[food_price] => 3000
)
)
https://stackoverflow.com/questions/50866828
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