有谁知道如何做一个简单的图片上传和显示在页面上。
这就是我要找的。
<img src>
将执行此操作,因为我需要显示不同的图像大小。这是我的代码。(其中一些是编辑过的,我是从here上得到的)
<style>
/* Image Designing Propoerties */
.thumb {
height: 75px;
border: 1px solid #000;
margin: 10px 5px 0 0;
}
</style>
<script type="text/javascript">
/* The uploader form */
$(function () {
$(":file").change(function () {
if (this.files && this.files[0]) {
var reader = new FileReader();
reader.onload = imageIsLoaded;
reader.readAsDataURL(this.files[0]);
}
});
});
function imageIsLoaded(e) {
$('#myImg').attr('src', e.target.result);
$('#yourImage').attr('src', e.target.result);
};
</script>
<input type='file' />
</br><img id="myImg" src="#" alt="your image" height=200 width=100>
发布于 2014-02-28 13:40:25
试试看,它支持多文件上传,
$('#multi_file_upload').change(function(e) {
var file_id = e.target.id;
var file_name_arr = new Array();
var process_path = site_url + 'public/uploads/';
for (i = 0; i < $("#" + file_id).prop("files").length; i++) {
var form_data = new FormData();
var file_data = $("#" + file_id).prop("files")[i];
form_data.append("file_name", file_data);
if (check_multifile_logo($("#" + file_id).prop("files")[i]['name'])) {
$.ajax({
//url : site_url + "inc/upload_image.php?width=96&height=60&show_small=1",
url: site_url + "inc/upload_contact_info.php",
cache: false,
contentType: false,
processData: false,
async: false,
data: form_data,
type: 'post',
success: function(data) {
// display image
}
});
} else {
$("#" + html_div).html('');
alert('We only accept JPG, JPEG, PNG, GIF and BMP files');
}
}
});
function check_multifile_logo(file) {
var extension = file.substr((file.lastIndexOf('.') + 1))
if (extension === 'jpg' || extension === 'jpeg' || extension === 'gif' || extension === 'png' || extension === 'bmp') {
return true;
} else {
return false;
}
}
其中#multi_file_upload为图片上传字段ID。
发布于 2019-04-06 07:48:56
<img id="output_image" height=50px width=50px\
<input type="file" accept="image/*" onchange="preview_image(event)">
<script type"text/javascript">
function preview_image(event) {
var reader = new FileReader();
reader.onload = function(){
var output = document.getElementById('output_image');
output.src = reader.result;
}
reader.readAsDataURL(event.target.files[0]);
}
</script>
发布于 2020-05-08 13:17:10
<li class="list-group-item active"><h5>Feaured Image</h5></li>
<li class="list-group-item">
<div class="input-group mb-3">
<div class="custom-file ">
<input type="file" class="custom-file-input" name="thumbnail" id="thumbnail">
<label class="custom-file-label" for="thumbnail">Choose file</label>
</div>
</div>
<div class="img-thumbnail text-center">
<img src="@if(isset($product)) {{asset('storage/'.$product->thumbnail)}} @else {{asset('images/no-thumbnail.jpeg')}} @endif" id="imgthumbnail" class="img-fluid" alt="">
</div>
</li>
<script>
$(function(){
$('#thumbnail').on('change', function() {
var file = $(this).get(0).files;
var reader = new FileReader();
reader.readAsDataURL(file[0]);
reader.addEventListener("load", function(e) {
var image = e.target.result;
$("#imgthumbnail").attr('src', image);
});
});
}
</script>
https://stackoverflow.com/questions/22087076
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