我正在尝试发送一些数字和散列使用服务器客户端。我使用UDP协议来做到这一点。我使用数字或散列创建一个包,并使用套接字发送它。客户端接收到它,因此只打印接收到的值。但是当我在客户端收到数字和散列时,我得到的不是相同的数字和散列。可能的问题是什么?
我给出了我的服务器和客户端代码,以及我在这里得到的输出。
服务器代码:
import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetAddress;
import java.nio.charset.StandardCharsets;
import java.security.MessageDigest;
import java.security.NoSuchAlgorithmException;
import java.security.SecureRandom;
import java.util.ArrayList;
import javax.xml.bind.DatatypeConverter;
public class main {
public static void main(String[] args) throws IOException, NoSuchAlgorithmException {
int n = 10;
SecureRandom rand = new SecureRandom();
ArrayList<String> clue = new ArrayList<String>();
ArrayList<String> cluenum = new ArrayList<String>();
MessageDigest digestnew = MessageDigest.getInstance("SHA-256");
byte[] finalmsgblock = "End".getBytes();
for(int i = 0; i < n; i++)
{
int num = rand.nextInt(100);
String num1 = Integer.toString(num);
byte[] num2 = digestnew.digest(num1.getBytes(StandardCharsets.UTF_8));
String num3 = "Clue: " + DatatypeConverter.printHexBinary(num2);
clue.add(i,num3);
cluenum.add(i, num1);
}
System.out.println(clue);
System.out.println(cluenum);
// Create a Socket
DatagramPacket packet, packet1;
InetAddress address;
DatagramSocket socket;
socket = new DatagramSocket();
address = InetAddress.getByName("127.0.0.1");
for(int i = 0; i < n; i++)
{
byte[] newdata = clue.get(i).getBytes(StandardCharsets.UTF_8);
packet = new DatagramPacket (newdata, newdata.length, address, 1502);
socket.send(packet);
System.out.println("Sent clue!");
byte[] newdata1 = cluenum.get(i).getBytes(StandardCharsets.UTF_8);
packet1 = new DatagramPacket (newdata1, newdata1.length, address, 1502);
socket.send(packet1);
System.out.println("Sent cluenum!");
}
DatagramPacket packet11 = new DatagramPacket (finalmsgblock, finalmsgblock.length, address, 1502);
socket.send(packet11);
}
}
客户端代码:
import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetAddress;
import java.nio.charset.StandardCharsets;
import java.security.SecureRandom;
import java.util.ArrayList;
import javax.xml.bind.DatatypeConverter;
public class main {
public static void main(String[] args) throws IOException {
int n = 10;
SecureRandom rand = new SecureRandom();
ArrayList<String> clue = new ArrayList<String>();
ArrayList<String> cluenum = new ArrayList<String>();
// Create the socket
int port = 1502;
DatagramSocket socket;
byte[] buf = new byte[10000];
DatagramPacket packet = new DatagramPacket(buf, buf.length);
InetAddress address = InetAddress.getByName("127.0.0.1");
socket = new DatagramSocket(port, address);
int i1 = 0;
int i2 = 0;
while(true)
{
socket.receive (packet);
byte[] data = new byte[packet.getLength()];
System.arraycopy(packet.getData(), packet.getOffset(), data, 0, packet.getLength());
String n1 = new String(data);
if(new String(data).equals("End"))
{
break;
}
else
{
if(n1.startsWith("Clue: "))
{
String n2 = (n1.replace("Clue: ", ""));
byte[] num = n2.getBytes(StandardCharsets.UTF_8);
String num1 = DatatypeConverter.printHexBinary(num);
clue.add(i1, num1);
i1 = i1 + 1;
}
else
{
byte[] num = n1.getBytes(StandardCharsets.UTF_8);
String num1 = DatatypeConverter.printHexBinary(num);
cluenum.add(i2, num1);
i2 = i2 + 1;
}
}
}
System.out.println(clue);
System.out.println(cluenum);
}
}
我得到的输出如下:
服务器输出:
[Clue: BBB965AB0C80D6538CF2184BABAD2A564A010376712012BD07B0AF92DCD3097D,
Clue: 44C8031CB036A7350D8B9B8603AF662A4B9CDBD2F96E8D5DE5AF435C9C35DA69,
Clue: 6E4001871C0CF27C7634EF1DC478408F642410FD3A444E2A88E301F5C4A35A4D,
Clue: A46E37632FA6CA51A13FE39A567B3C23B28C2F47D8AF6BE9BD63E030E214BA38,
Clue: C837649CCE43F2729138E72CC315207057AC82599A59BE72765A477F22D14A54,
Clue: CD70BEA023F752A0564ABB6ED08D42C1440F2E33E29914E55E0BE1595E24F45A,
Clue: 7902699BE42C8A8E46FBBB4501726517E86B22C56A189F7625A6DA49081B2451,
Clue: 19581E27DE7CED00FF1CE50B2047E7A567C76B1CBAEBABE5EF03F7C3017BB5B7,
Clue: EF2D127DE37B942BAAD06145E54B0C619A1F22327B2EBBCFBEC78F5564AFE39D,
Clue: 1A6562590EF19D1045D06C4055742D38288E9E6DCD71CCDE5CEE80F1D5A774EB]
[83, 84, 93, 82, 57, 89, 7, 9, 5, 50]
客户端输出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
我尝试过,但无法格式化客户端输出的
编辑:我试着只发送号码,但仍然不起作用。请让我知道可能的问题是什么?
发布于 2018-10-15 03:12:23
您正在从服务器发送十六进制编码的数据。那么你的客户就不应该再用DatatypeConverter.printHexBinary(num)
转换这个十六进制了
而不是由客户端执行
String n2 = (n1.replace("Clue: ", ""));
byte[] num = n2.getBytes(StandardCharsets.UTF_8);
String num1 = DatatypeConverter.printHexBinary(num);
clue.add(i1, num1);
只管去做
String n2 = (n1.replace("Clue: ", ""));
clue.add(i1, n2);
(并在客户端的else
子句中执行类似的操作。)
https://stackoverflow.com/questions/52799186
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