用java编写文件，更改大小写和编号
用java编写文件，更改大小写和编号
提问于 2018-10-16 13:56:31
我正在编写一个程序，通过执行以下操作来导入文本文件并创建输出文件：
在output.txt.
- Digits中显示的
- input.txt中所有字母的大小写颠倒，将以连字符分隔的单词列表显示数字中的数字。(例如，123 =1-2-3)。
- 还应在控制台中显示行号。
input.txt如下：
Here is A TEXT
File To Be
Processed FOR Lab09.
There are now 3459 ways to
DESIGN this kind of PROGRAM.
Here's hoping you can figure OUT 1, 2,
or 3 of these designs -
Or AT LEAST come close, even if
you don't find all 3459我不知道如何使用FileReader将Strings转换为char，以便正确打印到控制台和文件。对这个新的编码器的任何帮助都将不胜感激。
import java.io.*;
import java.util.*;
/**
* CSC110 Java 10am Lab09 Reading
*
* Writing Files file will create output file of the text formatted a certain way.
*/
public class Lab09 {
public static void main(String[] args) throws FileNotFoundException, IOException {
Scanner input = new Scanner(System.in);
System.out.print("Enter name of file: ");
String fileName = input.next();
System.out.println();
Scanner fileInput = new Scanner(new File(fileName));
FileWriter fw = new FileWriter("output.txt");
PrintWriter pw = new PrintWriter(fw);
while (fileInput.hasNext()) {
char c = fileInput.next().charAt(0);
String numberToWord = "";
pw.println(fileInput.nextLine().toUpperCase());
if (Character.isLowerCase(c)) {
System.out.println(fileInput.nextLine().toUpperCase());
pw.println(fileInput.nextLine().toUpperCase());
} else if (Character.isUpperCase(c)) {
System.out.println(fileInput.nextLine().toLowerCase());
if (Character.isDigit(c)) {
switch (c) {
case '1':
numberToWord = numberToWord + "one";
pw.println(fileInput.next(numberToWord));
System.out.println(numberToWord);
break;
case '2':
numberToWord = numberToWord + "two";
pw.println(fileInput.next(numberToWord));
System.out.println(numberToWord);
break;
case '3':
numberToWord = numberToWord + "three";
pw.println(fileInput.next(numberToWord));
System.out.println(numberToWord);
break;
case '4':
numberToWord = numberToWord + "four";
pw.println(fileInput.next(numberToWord));
System.out.println(numberToWord);
break;
case '5':
numberToWord = numberToWord + "five";
pw.println(fileInput.next(numberToWord));
System.out.println(numberToWord);
break;
case '6':
numberToWord = numberToWord + "six";
pw.println(fileInput.next(numberToWord));
System.out.println(numberToWord);
break;
}
}
}
}
pw.close();
fileInput.close();
}
}对不起，这很难看！我只是需要一些指导！任何帮助都是非常感谢的。
回答 1
Stack Overflow用户
回答已采纳
发布于 2018-10-16 14:07:01
每个数字都有一个数组
String nums [] = {"zero", "one", "two"}; // etc然后测试字符是否是一个数字，如果是，则减去'0‘的ascii。
char c = '2';
if (c >= '0' && c <= '9') {
int index = c - '0';
System.out.println(nums [index]);
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/52828749
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